Answer:
T = 0.225 s
Explanation:
The speed of a projectile at the highest point of its motion is the horizontal speed of the projectile. Considering the horizontal motion with negligible air resistance, we can use the following formula:
where,
T = Total time of ball in air = ?
R = Horizontal distance covered = 40 m
= horizontal speed = 9 m/s
Therefore,
<u>T = 0.225 s</u>
The net force on an object subject to friction is equal to the sum of the applied force and the frictional force.
Mathematically,
Here, m is mass of object and a is its acceleration. We take frictional force negative because it opposes the motion of object.
Given, ,
and
Substituting these values in above formula, we get
.
Thus, the acceleration of an object is
Answer:
relative vorticity is -0.868 × s-1
Explanation:
given data
air parcel at latitude = 18◦N
relative vorticity = 5.8 × 10^−5 s−1
to find out
relative vorticity
solution
we will apply here conservation of vorticity that is
ζ + f = constant
we know ζ initial = 2Ωsin(5π/18)
and f initial = 5.8 ×
and f final = 2Ωsin(π/18)
and here angular frequency Ω = 0.7272 × s-1
its mean
ζ initial - ζ final = f final - f initial
so
ζ final = ζ initial - f final + f initial
ζ final = - 2Ωsin(5π/18) + ( 2Ωsin(π/18) + 5.8 × )
ζ final = - 2(0.7272 × ) sin(5π/18) + ( 2(0.7272 ×
)sin(π/18) + 5.8 ×
)
ζ final = -0.868 × s-1
so relative vorticity is -0.868 × s-1
Answer:
a) the mass of the second car = 28000 kg
b) the amount of kinetic energy that was lost in the collision =
Explanation:
Given that:
mass of the train car = 6300 kg
speed of the train car = 12.0 m/s
mass of the second moving car = ???
speed of the second moving car = 2.2 m/s
After strike;
they both move with a speed = 4.00 m/s
a)
Using the conservation of momentum :
b)
To determine the amount of kinetic energy that was lost in the collision;
we will need to find the difference between the kinetic energy before the collision and after the collision;
i.e
Now; the kinetic energy that was lost in the collision is calculated as follows: