Simple ways to reduce heat loss include fitting carpets, curtains and draught excluders. It is even possible to fit reflective foil in the walls or on them. Heat loss through windows can be reduced by using double glazing. These special windows have air or a vacuum between two panes of glass.
Answer:
Following are the responses to the given choices:
Explanation:
For point a:
Using the acid and base which are strong so,
moles of 
(from
)
moles of 
(from 
)
So, 
i.e. 
mol of 
in excess in total volume 
i.e. concentration of 
![p[OH^{-}] = -\log [OH^{-}] = -\log [2 \times 10^{-4}\ mol] = 3.70](https://tex.z-dn.net/?f=p%5BOH%5E%7B-%7D%5D%20%3D%20-%5Clog%20%5BOH%5E%7B-%7D%5D%20%3D%20-%5Clog%20%5B2%20%5Ctimes%2010%5E%7B-4%7D%5C%20mol%5D%20%3D%203.70)
Since, 
so,
For point b:
moles of = from point a 
moles of (from):
1 mol neutralizes 1 mol of
So, 
i.e. 
in excess in the total volume of 
i.e. concentration of
Hence, ![pH = -\log [H^+] = -\log[2 \times 10^{-4}] = 3.70](https://tex.z-dn.net/?f=pH%20%3D%20-%5Clog%20%5BH%5E%2B%5D%20%3D%20-%5Clog%5B2%20%5Ctimes%2010%5E%7B-4%7D%5D%20%3D%203.70)
Answer: Therefore, the volume of a 0.155 M potassium hydroxide solution is 56.0 ml
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
According to the neutralization law,
where,
= molarity of 
solution = 0.338 M
= volume of solution = 25.7 ml
= molarity of solution = 0.155 M
= volume of solution = ?
= valency of = 1
= valency of = 1
Therefore, the volume of a 0.155 M potassium hydroxide solution is 56.0 ml
Answer:
To write a chemical equation, the reactants should be written on the left, and the products should be written on the right and the coefficients should be written next to the symbols of entities to indicate the number of moles of a substance produced used in the chemical reaction.
204.0920-It have 7 significant digits
