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RideAnS [48]
3 years ago
14

A force of 120.0 N is applied to a 3.00 kg block. What is the average acceleration of the block?

Physics
1 answer:
kirza4 [7]3 years ago
6 0

Explanation:

F = ma

120.0 N = (3.00 kg) a

a = 40.0 m/s²

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How many significant figures does 0.00340 have?
True [87]
Greetings!

"<span>How many significant figures does 0.00340 have?"...

A significant figure is:
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Therefore, this number has three significant figures:
3,4,0

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4 0
3 years ago
Read 2 more answers
A constant force of 8N acting on an object displaces it through a distance of 3.0 m in the direction of force. Calculate work-do
sweet-ann [11.9K]

\blue{\bold{\underline{\underline{Answer:}}}}

  • \green{\tt{Work\:done=24\:J}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline{\bold{Given :}}} \\  \tt: \implies Constant \: force(F) = 8 \: N \\  \\ \tt: \implies Displacement(s) = 3 \: m \\  \\ \red{\underline{\bold{To \: Find : }}} \\  \tt:  \implies Work \: Done(W.D) = ?

• <u>According to given question</u> :

\green{ \star} \tt \:  \theta \:  = 0 \degree \:  \:  \:  \: (Angle \: between \: force \: and \: displacement) \\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies Work \: Done = FS \: cos  \: \theta \\  \\  \tt:  \implies Work \: Done = 8 \times 3 \times cos \:0 \degree \\  \\ \green{ \circ} \tt \: cos  \: 0 \degree = 1  \\  \\  \tt:  \implies Work \: Done =24 \times 1 \\  \\   \green{\tt:  \implies Work \: Done =24 \: J}

5 0
2 years ago
"In a Young’s double-slit experiment, the separation between slits is d and the screen is a distance D from the slits. D is much
san4es73 [151]

Answer:

The number of bright fringes per unit width on the screen is, x=\dfrac{\lambda D}{d}      

Explanation:

If d is the separation between slits, D is the distance between the slit and the screen and \lambda is the wavelength of the light. Let x is the  number of bright fringes per unit width on the screen is given by :

x=\dfrac{n\lambda D}{d}

\lambda is the wavelength

n is the order

If n = 1,

x=\dfrac{\lambda D}{d}

So, the the number of bright fringes per unit width on the screen is \dfrac{\lambda D}{d}. Hence, the correct option is (B).

6 0
2 years ago
A 48 kg cart is sitting motionless at the top of the hill. At what height, did the cart start at, to reach 88435 J of energy at
svet-max [94.6K]

Answer : The height is 188 meters  

Explanation :   When the cart reached at the end from top of hill then the cart have potential energy .

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Potential energy = 88435 J

Mass of cart = 48 kg

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So, the height of the top is 188 meters.

7 0
3 years ago
Bob is pushing a box across the floor at a constant speed of 1.7 m/s, applying a horizontal force whose magnitude is 70 N. Alice
OlgaM077 [116]

Answer:

a) 70 N, b) b. Each initially applied a force bigger than static friction to get the box moving and accelerating, then when the desired final speed was achieved they reduced the force to make the net force zero.

Explanation:

a) A constant speed means that magnitude of friction force is equal to the magnitude of the external force. The friction force is directly proportional to the normal force, which is equal to the weight of the box. Therefore, the magnitude of the force is 70 N.

b) Alice used initially a greater force to accelerate the box up to needed speed and later reduced the external force to keep speed constant. The right choice is option b.

3 0
2 years ago
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