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RideAnS [48]
3 years ago
14

A force of 120.0 N is applied to a 3.00 kg block. What is the average acceleration of the block?

Physics
1 answer:
kirza4 [7]3 years ago
6 0

Explanation:

F = ma

120.0 N = (3.00 kg) a

a = 40.0 m/s²

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In a summer storm, the wind is blowing at a velocity of 8 m/s north. Suddenly in 3 seconds, the winds velocity is 23 m/s north.
cricket20 [7]

Answer:a=v-u/t

=23-8/3

=5m/s hope you got your answer

Explanation:

8 0
3 years ago
Physics Question - Matching
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3 years ago
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A football player kicks the ball through the goal posts with their foot and their toes are left stinging
GenaCL600 [577]

Answer: The foot kicked the ball with alot of force the ball had force too so their toes are left stinging

Explanation:

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3 years ago
Two spheres are cut from a certain uniform rock. One has radius 4.10 cm. The mass of the other is eight times greater.
Misha Larkins [42]

Answer:

8.2 cm

Explanation:

mass of one sphere = m

mass of other sphere = 8 m

Radius of first sphere = r = 4.10 cm

let the radius of another sphere is R

As we know that mass = volume x density

Let the density of the rock is d.

density of rock remains same.

density of small sphere = density of big sphere

mass of small sphere / volume of small sphere =

mass of big sphere / volume of big sphere

\frac{m}{\frac{4}{3}\pi r^{3}}=\frac{8m}{\frac{4}{3}\pi R^{3}}

R^{3}=8r^{3}

R = 2 r

R = 2 x 4.10 = 8.2 cm

Thus, the radius of big sphere is 8.20 cm.  

7 0
3 years ago
What is the threshold velocity vthreshold(ethanol) for creating Cherenkov light from a charged particle as it travels through et
AnnZ [28]

Explanation:

The velocity of light in a medium of refractive index n[tex] is given by,
[tex]v=\frac{c}{n}

v \text { is the velocity of light in the medium }

c \text { is speed of light in vacuum }

The exact value of speed of light in vacuum is 299792458 \mathrm{m} / \mathrm{s}.

For Cherenkov radiation to be emitted, the velocity of the charged particle traversing the medium must be greater than this velocity. Thus, the threshold velocity of for creating Cherenkov radiation is,

v_{\text {Cherenkov }} \geq \frac{c}{n}

v_{\text {threshod }}=\frac{c}{n}

For water n=1.33,[tex] thus the threshold velocity for producing Cherenkov radiation in water is,
[tex]v_{\text {threatold }(\text { water })} &=\frac{299792458 \mathrm{m} / \mathrm{s}}{1.33}

=225407863 \mathrm{m} / \mathrm{s}

=2.254 \times 10^{8} \mathrm{m} / \mathrm{s}

For ethanol n=1.36[tex], thus the threshold velocity for producing Cherenkov radiation in water is,
[tex]v_{\text {threstold }( \text { ettanol) } } &=\frac{299792458 \mathrm{m} / \mathrm{s}}{1.36}

=220435630 \mathrm{m} / \mathrm{s}

=2.204 \times 10^{8} \mathrm{m} / \mathrm{s}

6 0
3 years ago
Read 2 more answers
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