The Pythagorean theorem computed shows that the length of the guy wire, to the nearest foot, is 207 ft.
<h3>How to solve the length?</h3>
Here, we have two similar right triangles, ΔABE and ΔCDE.
CD = 11 ft
DE = 2 ft
BD = 35 ft
First, find AB:
AB/11 = (35 + 2)/2
AB/11 = 37/2
Cross multiply
AB = (37 × 11)/2
AB = 203.5 ft
Then, apply Pythagorean Theorem to find AE:
AE = √(AB² + BE²)
AE = √(203.5² + 37²)
AE = 207 ft
Therefore, the length of the guy wire is 207 ft.
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Answer: x = - 3.5
Step-by-step explanation:
Rewrite the equation by completing the square.
4x2 + 28x + 49 = 0
Completing the square method :
Divide through by the Coefficient of x^2
x^2 + 7x + (49/4) = 0
a = 1, b = 7, c = 49/4
Move c to the right side of the equation
x^2 + 7x = - 49/4
Complete the square on the left hand side by squaring its half of the x term
(7/2)^2 = (49/4)
Add the output to both sides of the equation
x^2 + 7x + (49/4) = - (49/4) + (49/4)
(x + 7/2)^2 = 0
Square root of both sides
x + 7/2 = 0
x = - 7/2
x = - 3.5
40 students
12-A
18-B
40-12=28
28-18=10
10/40 did not vote.
25% did not vote
10 is one fourth of 40
fourth of 100% is 25%
Answer:
Its A
Step-by-step explanation:
Standard equation: y=mx+b
x+y=0
-x -x
y=-x+0
<h2>
The circumference of small size, medium size and large size of pizzas are 25.12 inches, 31.4 inches and 37.68 inches.</h2>
Step-by-step explanation:
Given,
The diameter of small pizza = 8 inches,
The diameter of medium pizza = 10 inches and
The diameter of large pizza (d) = 11 inches
To find, the circumference of each size of pizza = ?
We know that,
The circumference of the circle = 
∴ The circumference of small size of pizza = 3.14 × 8 = 25.12 inches
The circumference of medium size of pizza = 3.14 × 10 = 31.4 inches
Also,
The circumference of large size of pizza = 3.14 × 12 = 37.68 inches
Thus, the circumference of small size, medium size and large size of pizzas are 25.12 inches, 31.4 inches and 37.68 inches.
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https://brainly.ph/question/1009095