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4 years ago

Which comes first domain or range

Mathematics

2 answers:

GarryVolchara [31]4 years ago

8 0

In order for this to work.range comes first because for example a 100-500 range between the phone cost

Alisiya [41]4 years ago

6 0

They are intertwined the domain is the allowed values of the independent varialbles and the range is the allowed values of the dependent variable.

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How many 3-digit numerical passwords are there if a digit cannot be repeated?

alexgriva [62]

The first digit of the password can be any of the ten digits - 10 possibilities.
A digit cannot be repeated, so the second digit can be any digit except the one you chose for the first digit - 9 possibilities.
The third digit can be any digit except the digits you chose for the first and second digit - 8 possibilities.

Using the rule of product:
$10 \times 9 \times 8=720$

There are 720 passwords.

5 0

3 years ago

The function y=h(x) is defined as follows:

Lunna [17]

Answer:

h(1) = 1

h(4) = 5

Step-by-step explanation:

Since 1 is in the interval 1 ≤ x ≤ 3, you must substitute 1 into the expression $x^{3}$

So, h(1) = $1^{3}$ = 1

Since 4 is in the interval x > 3, and all values of x > 3 gives an output of 5, then h(4) = 5

7 0

3 years ago

ANSWER TO BE NAMED BRAINLIEST GET A THANK YOU A FOLLOW AND 25 PPTS

Svet_ta [14]

Answer:

192 cm^3

Step-by-step explanation:

Volume for rectangular prism is V=l*w*h

V=8*4*6=32*6=192

So volume is 192 cm^3

8 0

3 years ago

Prove that if {x1x2.......xk}isany

Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where $n\geq 2$ . If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set $X= (x_1, x_2,....,x_n)$ is linearly dependent, so then by definition we have scalars $c_1,c_2,....,c_n$ in C such that:

$c_1 x_1 +c_2 x_2 +.....+c_n x_n =0$

And not all the scalars $c_1,c_2,....,c_n$ are equal to 0.

Since at least one constant is non zero we can assume for example that $c_1 \neq 0$ , and we have this:

$c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n$

We can divide by c1 since we assume that $c_1 \neq 0$ and we have this:

$v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n$

And as we can see the vector $v_1$ can be written a a linear combination of the remaining vectors $v_2,v_3,...,v_n$ . We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select $v_1$ and we have this:

$v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n$

For scalars defined $c_2,c_3,...,c_n$ in C. So then we have this:

$v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0$

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0

3 years ago

Write an equation that models the sequence 400, 200, 100, 50, ...

Julli [10]

You're starting at 400. Each time you're cutting in half.

So the common ratio is 1/2 which means the equation is

$\Large y = 400(1/2)^{x-1}$

which is in the geometric sequence format. So the answer is choice D

3 0

3 years ago

Read 2 more answers