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sattari [20]
3 years ago
10

Can someone pls help me answer this I’ll give brainliest to whoever actually answers it

Physics
1 answer:
sergejj [24]3 years ago
7 0

Answer:

Limestone classifacation: sedimentary rock

Sandstone: sedimentary rock

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The work that is done when twice the load is lifted twice the distance is _______. View Available Hint(s)for Part A The work tha
anygoal [31]

The work that is done when twice the load is lifted twice the distance is

four times as much

The net work performed by forces acting on an object equals the change in kinetic energy, according to the work-energy theorem.

when an item slows down, the net work applied to it decreases, its change in kinetic energy is negative, and its ultimate kinetic energy is less than its starting kinetic energy. When an item accelerates, positive net work is done on it. All the forces acting on an item must be taken into consideration when determining the net work. You will obtain an incorrect result if you exclude any forces that affect an item or if you add any forces that do not affect it.

Hence The work that is done when twice the load is lifted twice the distance is four times as much

Learn more about Work here

brainly.com/question/25573309

#SPJ4

3 0
2 years ago
Stewart (70 Kg) is attracted to Ms. Little (60 Kg) who sits 2 m away. What is the gravitational attraction between them? G=6.67×
ikadub [295]

Happy Holidays!

We can use the following equation to solve for the gravitational force:

\large\boxed{F_g = G\frac{m_1m_2}{r^2}}

Fg = force due to gravity (N)

G = Gravitational constant

m1,m2 = masses of the objects (kg)

r = distance between the objects (m)

Plug in the given values into the equation:

F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}

7 0
3 years ago
Help pls!
Yuki888 [10]

A series circuit is a closed circuit in whicj the current flows through one path.

8 0
3 years ago
Please help on this one?
SSSSS [86.1K]
I think it would be near the sun due.to high rays of sun
8 0
3 years ago
Read 2 more answers
72) What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 (formula weight = 164 g/mol) in 115
Rina8888 [55]

<u>Answer:</u> The freezing point of solution is -3.34°C

<u>Explanation:</u>

Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of calcium nitrate follows:

Ca(NO_3)_2(aq.)\rightarrow Ca^{2+}(aq.)+2NO_3^-(aq.)

The total number of ions present in the solution are 3.

  • To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (Ca(NO_3)_2) = 11.3 g

M_{solute} = Molar mass of solute (Ca(NO_3)_2) = 164  g/mol

W_{solvent} = Mass of solvent (water) = 115 g

Putting values in above equation, we get:

\text{Molality of }Ca(NO_3)_2=\frac{11.3\times 1000}{164\times 115}\\\\\text{Molality of }Ca(NO_3)_2=0.599m

  • To calculate the depression in freezing point, we use the equation:

\Delta T=iK_fm

where,

i = Vant hoff factor = 3

K_f = molal freezing point depression constant = 1.86°C/m.g

m = molality of solution = 0.599 m

Putting values in above equation, we get:

\Delta T=3\times 1.86^oC/m.g\times 0.599m\\\\\Delta T=3.34^oC

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T=\text{freezing point of water}-\text{freezing point of solution}

\Delta T = 3.34 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

3.34^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-3.34^oC

Hence, the freezing point of solution is -3.34°C

4 0
4 years ago
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