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3 years ago

Name two objects that both use electric motors and are commonly found in houses

Physics

2 answers:

strojnjashka [21]3 years ago

8 0

Answer:

There are many common household objects that feature electric motors, such as vacuum cleaners, blenders, the sink garbage disposal, and the hair dryer. There are also small electric motors in common toys, such as in the tiny cars that make them go. Some office supplies have them too: pencil sharpeners, coffee-bean grinders, ceiling fans, the printer, and even the vibrator in a cell phone!

Explanation:

<em>God Bless!</em>

Natali [406]3 years ago

3 0

There's the fan over the stove and in the microwave oven, the dispose-all under the sink, the blender, the washer, the dryer, vacuum cleaner, hair dryer, and there are many in a computer.

Hope this helps!

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Resonance in air column is used in which of these musical instruments

zvonat [6]

Answer: The correct answer is "trumpet".

Explanation:

Resonance occurs when the applied frequency on the object is equal to the natural frequency of the object.

Wind instruments use resonance in the air column to amplify the sound. It makes the sound louder. Sound is produced by using lips or vibrating reeds or buzzing sound into the mouthpiece.

Therefore, resonance in air column is used in trumpet musical instruments.

7 0

3 years ago

Read 2 more answers

A flat, circular, steel loop of radius 75 cm is at rest in a uniform magnetic field, as shown in an edge-on view in the figure (

SIZIF [17.4K]

The solution to the questions are given as

$t=40.39 \mathrm{sec}$
$\varepsilon &=(0.12v)e^{0.057t}$
the direction of induced current will be Counterclock vise.

<h3>What is the direction of the current induced in the loop, as viewed from above the loop.?</h3>

Given, $B(t)=(1.4 T) e^{-0.057 t}$

$$\varepsilon m f(\varepsilon)=-\frac{d \phi_{B}}{d t}$

$\quad$ and, $\phi_{B}=\int B \cdot d A=\int B \cdot d A \cdot \cos \theta$$

$\begin{aligned}\text { Here, } \theta &=30^{\circ} ; \\A &=\pi r^{2} \\a n \delta, R &=0.75 \mathrm{~m} \\\therefore \varepsilon &=-\frac{d}{d t}(B A \cdot \cos \theta)=-A \cdot \cos \theta \cdot \frac{d}{d t}(B(t)) \\\therefore \varepsilon &=-\pi R^{2} \cdot \cos \theta \cdot \frac{d}{d t}\left(e^{-0.057 t}\right)(1.4 T) \\\therefore \varepsilon &=+\pi(0.75)^{2} \cdot \cos 30 \cdot(0.057)(1.4) \cdot e^{-0.057 t}\left\{\because \frac{d}{d t} e^{-x}=-x \cdot e^{-x} .\right.\end{aligned}$

$\varepsilon &=(0.12v)e^{0.057t}$

(b) $Here, $\varepsilon_{0}=0.12 \mathrm{~V} \quad\left(a t_{2} t=0 \mathrm{sec}\right)$$

$\begin{aligned}&\therefore 1 . \varepsilon_{0}=\varepsilon_{0} \cdot e^{-e .057 t} \\&\therefore e^{0.057 t}=10 \quad \text { (taking log both thesides) } \\&\therefore 0.057 t=\ln (10)=2.303 \\&\therefore t=40.39 \mathrm{sec}\end{aligned}$

In conclusion, the direction of the induced current will be Counterclockwise.

Read more about current

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4 0

2 years ago

A proton in a cyclotron is moving with a speed of 2.97×107 m/s in a circle of radius 0.568 m. 1.67 × 10−27 kg is the mass of the

vivado [14]

Answer:

B = 0.546 T, F = 2.59 10⁻¹² N

Explanation:

The magnetic force is

F = q v x B

We can calculate the magnitude of the force and find the direction by the right hand rule

F = q v B sin θ

Let's use Newton's second law

F = m a

Acceleration is centripetal

a = v² / r

We substitute

q v B sin θ = m v² / r

The angle between the field and the radius of the circle is 90º so sin 90 = 1

q B = m v / r

B = m v / q r

Let's calculate ’

B = 1.67 10⁻²⁷ 2.97 10⁷ / (1.60 10⁻¹⁹ 0.568)

B = 0.546 T

The foce is

F = q v B

F = 1.60 10⁻¹⁹ 2.97 10⁷ 0.546

F = 2.59 10⁻¹² N

3 0

3 years ago

An ammeter with a resistance of 5.0 ohm is connected in series with a 3.0V cell and a lamp rated at 300 mA, 3V. Calculate the cu

Alex

Answer:

I = 0.2 A

Explanation:

Lamp is rated at 300 mA

I_lamp = 0.3 A

Voltage is; V = 3V

Thus; Resistance is given by;

R = V/I

R = 3/0.3

R = 10 ohms

Now, since the ammeter of 5 ohms is connected in series with the lamp. Thus equivalent resistance;

R_eq = 10 + 5

R_eq = 15 ohms

Ammeter current will be;

I = V/R_eq

I = 3/15

I = 0.2 A

3 0

2 years ago

Apakah yang dimaksud dengan gaya

tangare [24]

Nah gaya seperti titik fashion seperti apa yang Anda mana dan hal-hal seperti itu. (tell me if you cant understand)

8 0

3 years ago

Read 2 more answers