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djverab [1.8K]
2 years ago
8

Give proof that mass is constant and weight keeps changing.​

Physics
1 answer:
shutvik [7]2 years ago
7 0

The mass of an object stays the same wherever it is, but its weight can change. This happens if the object goes where the gravitational field strength is different from the gravitational field strength on Earth, such as into space or another planet.
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A ball is tossed straight up from the surface of a small, spherical asteroid with no atmosphere. The ball rises to a height equa
alukav5142 [94]

Answer:

d. equal to one-fourth the acceleration at the surface of the asteroid.

Explanation:

The explanation is attached as a picture with this answer

Newton's law of universal gravitation is being used to compare the accelerations at the surface and at the top of the ball's path.

as it can be seen in the explanation that the proportional form of the equation is used because we do not need to necessarily use to final form with "G" for comparison calculations.

As per the given scenario only difference between the two points in the gravitational field is the distance from center of the spherical asteroid, i.e. r.

It is  taken 2r for the top is the path. hence we obtain (1/4)g as our answer.

4 0
3 years ago
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Please help me I am desperate this is due now
elena55 [62]

Answer:

Distance travelled is 7 meters and the displacement is 3 meters

7 0
2 years ago
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A cylindrical container with a cross-sectional area of 66.2 cm2 holds a fluid of density 856 kg/m3 . At the bottom of the contai
Ugo [173]

Answer:

A. h = 2.15 m

B. Pb' = 122 KPa

Explanation:

The computation is shown below:

a)  Let us assume the depth be h

As we know that

Pb - Pat = d \times g \times h \\\\ ( 119 - 101) \times 10^3 = 856 \times 9.8 \times h

After solving this,  

h = 2.15 m

Therefore the depth of the fluid is 2.15 m

b)

Given that  

height of the extra fluid is

h' = \frac{2.35 \times 10^{-3}}{ area} \\\\ h' = \frac{2.35 \times 10^{-3}} { 66.2 \times 10^{-4}}

h' = 0.355 m

Now let us assume the pressure at the bottom is Pb'

so, the equation would be

Pb' - Pat = d \times g \times  (h + h')\\\\Pb' = 856 \times 9.8 \times ( 2.15 + 0.355) + 101000

Pb' = 122 KPa

3 0
3 years ago
Why is an element considered a pure substance?
ElenaW [278]

Answer:

Explanation:

right

8 0
2 years ago
A driver travels 4.1 km west, 17.3 km north, and finally 1.2 km at an angle of 65.4 degree north of west. What is the driver’s d
jek_recluse [69]

Answer:

Explanation:

We shall represent each displacement in vector form .

i will represent east , j will represent north .

D₁ = 4.1 west = - 4.1 i

D₂ = 17.3 north = 17.3 j

D₃ = - 1.2 cos65.4 i + 1.2 sin65.4 j

= - .5 i + 1.09 j

Total displacement

= D₁ + D₂ + D₃

=  - 4.1 i + 17.3 j - .5 i + 1.09 j

D = - 4.6 i + 18.39 j

magnitude of D

= √ ( 4.6² + 18.39² )

= √ (21.16 + 338.2 )

= √359.36

= 18.95 km .

Final displacement = 18.95 km .

5 0
3 years ago
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