2 Blocks 1 and 2 rest on rough surfaces with coefficient of frictions ¢1 and ¢2 respectively. The blocks

Engineering

1 answer:

Amiraneli [1.4K]3 years ago

4 0

Answer:

100N
25N

Explanation:

a) On the verge of tipping over, reaction acts at the corner A

When slippage occurs,

Block moves w/ const. velocity  equilibrium

Three-force member: reaction at A must pass through B

tan b/2h, h b/ 2 θ µ = = ∴= k k ( µ )

b) When slippage occurs,

Block moves w/ const. velocity  equilibrium

Three-force member: reaction at C must pass through G

k tanθ µ =

tan x/ H/2 , x H/2

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A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are 19.636

luda_lava [24]

Answer:

The original length of the specimen is found to be 76.093 mm.

Explanation:

From the conservation of mass principal, we know that the volume of the specimen must remain constant. Therefore, comparing the volumes of both initial and final state as state 1 and state 2:

Initial Volume = Final Volume

πd1²L1/4 = πd2²L2/4

d1²L1 = d2²L2

L1 = d2²L2/d1²

where,

d1 = initial diameter = 19.636 mm

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L1 = (19.661 mm)²(75.9 mm)/(19.636 mm)²

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Answer:

The p-value of the hypothsis 0.00135

Explanation:

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2 years ago

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Answer:

C) 43,2°C

Explanation:

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where: