PV=nRT
P= ? atm
V= 2 L
T= 423 K
n= 2.3 moles
R= 0.08205
(P)(2)=(2.3)(0.08205)(423)
P= (79.826445)/(2)
P= 39.9132225 atm
The answer is 123
Brainliest??
Answer:
Mass of NaBr produced = 23.67 g
Explanation:
Given data:
Mass of AgBr = 42.7 g
Mass of NaBr produced = ?
Solution:
Chemical equation:
2Na₂S₂O₃ + AgBr → NaBr + Na₃(Ag(S₂O₃)₂
Number of moles of AgBr:
Number of moles = mass/molar mass
Number of moles = 42.7 g/ 187.7 g/mol
Number of moles = 0.23 mol
now we will compare the moles of AgBr with NaBr.
AgBr : NaBr
1 : 1
0.23 : 0.23
Mass of NaBr:
Mass = number of moles × molar mass
Mass = 0.23 mol × 102.89 g/mol
Mass = 23.67 g
Answer:
80.2
Explanation:
we subtract 18.2 from the total percentage which is 100%
Answer: you are the imposter you killed red then vented in admin
Explanation:
