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3 years ago

Convert Fahrenheit temperatureto Kelvin scales

2 answers:

8 0

°C + 273.15 = K. The basic formula for converting Fahrenheit into Celsius is (°F − 32) × 5/9 = °C. To convert Fahrenheit degrees into Kelvins, (°F − 32) × 5/9 + 273.15 = K.

12345 [234]3 years ago

4 0

Answer:

K = (F – 32)5/9 + 273.15

Explanation:

You basically convert Fahrenheit to Celcius and then to Kelvin

Here's the entire formula:

K = (x °F – 32)5/9 + 273.15

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The system co2(g) + h2(g) ⇀↽ h2o(g) + co(g) is at equilibrium at some temperature. at equilibrium a 4.00 l vessel contains 1.00

Marina CMI [18]

<u>Answer:</u> The moles of $CO_2$ added to the system is 7.13 moles

<u>Explanation:</u>

We are given:

Moles of $CO_2$ at equilibrium = 1.00 moles

Moles of $H_2$ at equilibrium = 1.00 moles

Moles of $H_2O$ at equilibrium = 2.40 moles

Moles of $CO$ at equilibrium = 2.40 moles

Volume of the container = 4.00 L

Concentration is written as:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}$

The given chemical equation follows:

$CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}$

Putting values in above equation, we get:

$K_c=\frac{(\frac{2.40}{4.00})\times (\frac{2.40}{4.00})}{(\frac{1.00}{4.00})\times (\frac{1.00}{4.00})}\\\\K_c=5.76$

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of CO = 0.791 mol/L

Volume of solution = 4.00 L

Putting values in above equation, we get:

$0.791M=\frac{\text{Moles of CO}}{4.00L}\\\\\text{Moles of CO}=(0.791mol/\times 4.00L)=3.164mol$

Extra moles of CO = (3.164 - 2.40) = 0.764 moles

Let the moles of $CO_2$ needed be 'x' moles.

Now, equilibrium gets re-established:

$CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)$

Initial: 1.00 1.00 2.40 2.40

At eqllm: (0.236+x) 0.236 3.164 3.164

Again, putting the values in the expression of $K_c$ , we get:

$5.76=\frac{(\frac{3.164}{4.00})\times (\frac{3.164}{4.00})}{(\frac{0.236+x}{4.00})\times (\frac{0.236}{4.00})}\\\\5.76=\frac{10.011}{0.056+0.236x}\\\\x=7.13$

Hence, the moles of $CO_2$ added to the system is 7.13 moles

4 0

3 years ago

Gas laws mad question under it

ozzi

Answer:

what are you asking tho?

Explanation:

Thx for the Free points tho.

5 0

3 years ago

I have a question on my Chem homework. It's asking "How many molecules of N2O4 are in 76.3 g N2O4? The molar mass of N2O4 is 92.

evablogger [386]

Here, Molar mass of N2O4 = 92.02 g/mol
So, Number of molecules in 1 mole (92.02 g) = 6.023 * 10²³
Number of molecules in 76.3 g = 6.023 * 10²³ / 92.02 * 76.3
= 6.023 * 10²³ / 1.20
= 5 * 10²³

In short, Your Answer would be approx. 5 * 10²³ molecules

Hope this helps!

7 0

4 years ago

write the balanced chemical equation for the following word equation. sodium+sulphate Acidsodium sulphate +hydrogen

Oksanka [162]

Answer:

<h3>I HOPE ITS RIGHT IF NOT THEN SORRY</h3>

HAVE A GREAT DAY :)

7 0

3 years ago

Read 2 more answers

Calculate the molarity of 8.42 x 102 mL of solution containing 22.4 g of potassium iodide.

givi [52]

Answer:

Molarity = 0.154 M

Explanation:

Given data:

Volume of solution = 8.42 × 10² mL ( 8.42 × 10² /1000 = 0.842 L)

Mass of potassium iodide = 22.4 g

Molarity of solution = ?

Solution:

Number of moles of potassium iodide:

Number of moles = mass/molar mass

Number of moles = 22.4 g/ 166.0 g/mol

Number of moles = 0.13 mol

Molarity:

Molarity = number of moles / volume in L

Molarity = 0.13 mol / 0.842 L

Molarity = 0.154 M

8 0

3 years ago

Convert Fahrenheit temperatureto Kelvin scales​

Convert Fahrenheit temperatureto Kelvin scales