Question

If a Geiger counter that is 1 m away from a small source reads 50 counts per minute, what will its reading be 2 m from the source?

Answer 1

as the amount of radiation received is proportional to 1/d^2

2m from source

for 1m readings are 50 count per minute

for 2m =   50 / (2)^2

                   50 / 4   =  12.5 count per minute

Answer 2

Answer:

$12.5counts/min$

Explanation:

Hello,

In this case, the radiation from a point source follows an inverse-square law wherein the quantity of radiation is proportional to 1/d², where d is distance. Therefore, 2 m away from the source, the counts will be:

$Counts/min=\frac{50counts/min}{2^2} =12.5counts/min$

Best regards.