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2 years ago

Question 11 of 29

Physics

1 answer:

lara [203]2 years ago

3 0

Answer:

the answer is a

Explanation:

wawawawawawawawawawawawawa

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A student gives a 5.0 kg box a brief push causing the box to move with an initial speed of 8.0 m/s along a rough surface. The bo

WITCHER [35]

Answer:

The time taken to stop the box equals 1.33 seconds.

Explanation:

Since frictional force always acts opposite to the motion of the box we can find the acceleration that the force produces using newton's second law of motion as shown below:

$F=mass\times acceleration\\\\\therefore acceleration=\frac{Force}{mass}$

Given mass of box = 5.0 kg

Frictional force = 30 N

thus

$acceleration=\frac{30}{5}=6m/s^{2}$

Now to find the time that the box requires to stop can be calculated by first equation of kinematics

The box will stop when it's final velocity becomes zero

$v=u+at\\\\0=8-6\times t\\\\\therefore t=\frac{8}{6}=4/3seconds$

Here acceleration is taken as negative since it opposes the motion of the box since frictional force always opposes motion.

5 0

3 years ago

What is density?

a_sh-v [17]

Answer:

B- The amount of matter in a certain

amount of space

Explanation:

Density is the amount of matter an object has in a certain space. To find density, divide the mass of an object by the volume of an object.

8 0

3 years ago

Read 2 more answers

If you pull a resistant puppy with its leash in a horizontal direction, it takes 80 N to get it going. You can then keep it movi

netineya [11]

Answer:

The coefficient of static friction between the puppy and the floor is 0.7273.

Explanation:

The horizontal force applied to move the puppy from a steady state has to be greater than the force of static friction, after it is moving the force needs to be equal to be greater than the force of dynamic friction in order to maintain its movement. The force of static friction is given by:

$F_s = \mu_s*N$

Where $F_s$ is the static friction force, $\mu_s$ is the coefficient of static friction and $N$ is the normal force. Since there's no angle on the flor the normal force is equal to the weight of the puppy, therefore, $N = 110\text{ N}$ , to make the puppy moving we need to use a force of 80 N, therefore, $F_s = 80 \text{ N}$ , so we can solve for the coefficient as shown below:

$80 = \mu_s*110\\\mu_s = \frac{80}{110} = 0.7273\\$

The coefficient of static friction between the puppy and the floor is 0.7273.

5 0

3 years ago

Need help 8th grade work

Alisiya [41]

1) Ecology

2) Food Web

3) Trophic Level

4) Producer

5) Autotroph

6) Consumer

7) Heterotroph

8) Decomposer

Hope tHis Helps ._.

6 0

3 years ago

Read 2 more answers

As a diligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.01 m l

Valentin [98]

Answer:

The strength of the magnetic field is $75.6\ \mu T$ .

Explanation:

Given that,

Length of the rod, L = 1.01 m

Speed with which the rod is moving, v = 3.47 m/s

We need to find the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.265 mV across the rod. When the rod is moving with some speed, an emf gets induced and it is given by :

$\epsilon=Blv$

B is magnetic field

$B=\dfrac{\epsilon}{lv}\\\\B=\dfrac{0.265\times 10^{-3}}{1.01\times 3.47}\\\\B=75.6\ \mu T$

So, the strength of the magnetic field is $75.6\ \mu T$ .

6 0

3 years ago