A 43 kg box is being pushed and pulled by
1 answer:
Answer:
a = - 0.209 [m/s²]
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
We will take the positive forces to the right and the negative forces to the left.
The negative sign means that the box accelerates in a negative direction to the left.
You might be interested in
Answer:
(a) Ey is negative
(b) The magnitude of the electric field is E = 171.429 V/m
(c) The potential difference between points B and C is 17.1429 V
Explanation:
(a) Here, we have the potentials given by;
with point A at y = 8.00 cm and point B at point y = 15.0 cm
where point B is at a higher potential than point A, that is the electric potential is from;
B with y = 15.0 cm to A with y = 8.0 cm which means
decreases as y increases or
is negative.
(b) The magnitude of the electric field is given by
The work done to move a charge from B to A is
where
∴
E = 171.429 V/m
(c) Here we have point C x = 5.00 cm and y = 5.00 cm
Therefore we have the distance from B to C given by
Where 10.00 cm = 0.01 m
E = V/Δy
Therefore, V = Δy·E
For , Δy =
and we have,