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Jet001 [13]
2 years ago
6

Which of the following is a common property of both strong acid and strong base?

Chemistry
2 answers:
kifflom [539]2 years ago
4 0

Answer:

They are good electrolytes

Gekata [30.6K]2 years ago
3 0

Answer:please can you help me with the last question that I asked I will help you if you help me please help

Explanation:

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Arrange steps in order to describe what happens to a gas when it is cooled
AnnZ [28]

A) Particles of gas move slower.

B) Gas changes to liquid.

C) The gas loses thermal energy.

D) Gas particles decrease.

3 0
3 years ago
1 gallon is how many mm
leva [86]

Answer:

0.133681 (cubic foot)

Explanation:

6 0
2 years ago
At the beginning of an experiment, a scientist has 176 grams of radioactive goo. After 165 minutes, her sample has decayed to 5.
Paul [167]
The half-life equation is written as:

An = Aoe^-kt

We use this equation for the solution. We do as follows:

5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes? 
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE


Find a formula for G(t) , the amount of goo remaining at time t.G(t)=? 

G(t) = 176e^-0.02t

How many grams of goo will remain after 50 minutes? 

G(t) = 176e^-0.02(50) = 64.75 g
6 0
3 years ago
¿How do the products of the reaction to the phenol red test and the splint test? Please help me it's for today.! :((​
laila [671]

Answer:

The answer in this question is show you made Sodium Hydroxide and Hydrogen Gas.In order to do the products of the reaction relate to the phenol red test and the splint test you need to show that you made Sodium Hydroxide and Hydrogen Gas. Show that you made Sodium Hydroxide and Hydrogen Gas so that the products of the reaction relate to the phenol red test and the splint test.

5 0
2 years ago
Draw the curved arrow mechanism for the formation of an acetal from acidic methanol and 4-methylpentan-2-one in the fewest steps
morpeh [17]

Answer:

See explanation below

Explanation:

This reaction is known as Ketone hydrolisis in acid medium. This involves the formation of an hemi cetal, and then, the acetal. This is often used to convert ketones or aldehydes in ethers.

The first step involves the reaction with the acid. The carbonile reacts with the acid and forms an alcohol there. The next step is the reaction of the alcohol, in this case, the methanol to form the hemi cetal. Then in the third step, we repeat the first step, using acid to turn the OH group into a great leaving group such water. Then the water leaves the molecule, leaving the space wide open in the next step for methanol, and the acetal is formed.

See picture for the curved arrow mechanism

7 0
3 years ago
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