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jarptica [38.1K]
3 years ago
6

Which groups of the periodic table want to gain electrons? What kind(s) of elements are these groups

Chemistry
1 answer:
lukranit [14]3 years ago
6 0

Answer:

Elements that are metals tend to lose electrons and become positively charged ions called cations. Elements that are nonmetals tend to gain electrons and become negatively charged ions called anions. Metals that are located in column 1A of the periodic table form ions by losing one electron.

Explanation:

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George has a mass of 65kg. What would George weigh on the Moon? (The gravitational field strength on the Moon is 1.6N/kg.)
dem82 [27]

Answer:

\boxed{\large \text{104 N}}  

Explanation:

\text{Weight} = \text{65 kg} \times \dfrac{\text{1.6 N}}{\text{1 kg}} = \textbf{104 N}\\\\\text{George would weigh $\boxed{\large \textbf{104 N}}$ on the moon}

5 0
2 years ago
Read 2 more answers
What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm
Zanzabum

Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

Explanation:

<u>Part I :</u>

n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}

n = 4.9983

n = 4.99 moles

(Note : You can also take n = 5 mole )

Molar mass of gold = 196.96 g/mole

This means, 1 mole of gold(Au) contain = 196.96 grams

So, 4.99 moles of gold contain = 5\times 196.96 g

4.99 moles of gold contain = 984.8 g

Mass of {3.01\times 10^{24}} atoms of gold = 984.5 g

<u>Part II :</u>

Density of Gold = 19.32 g/cm^{3}

Volume of the cuboid = length\times breadth\times height

Volume of the gold bar =6.00\times 4.25\times 2.00

Volume of the gold bar = 51cm^{3}

Using formula,

Density = \frac{mass}{Volume}

Mass = Density\times Volume

Mass = 19.32 \times 51

Mass = 985.32 g

So, A  gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of <u>985.32 g</u>

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

3 0
3 years ago
3. The temperature of a fixed mass of gas in a rigid container is decreased from 127.00 degrees
Sonbull [250]

Answer:

750mmHg

Explanation:

The following data were obtained from the question:

T1 = 127°C = 127 +273 = 400K

T2 = 27°C = 27 +273 = 300K

P1 = 1000mmHg

P2 =?

P1/T1 = P2/T2

1000/400 = P2 /300

Cross multiply

400 x P2 = 1000 x 300

Divide both side by 400

P2 = (1000 x 300)/400

P2 = 750mmHg

Therefore, the new pressure after cooling is 750mmHg

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