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3 years ago

The three aspects of the measuring process are units, systems, and instruments.

Chemistry

2 answers:

skelet666 [1.2K]3 years ago

6 0

Answer:

false

Explanation:

<h3>the ans is false</h3>

<h3>hope it helps</h3>

lawyer [7]3 years ago

4 0

Answer:

the answer for that is false

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Which best describes the effect of J. J. Thomson’s discovery?

worty [1.4K]

Answer:

A. The accepted model of the atom was changed.

Explanation:

Thomson described an atom that has the protons uniformly distributed within a circular atom with the electrons embedded . However, it cannot explain the emission of electrons from the surfaces of metals like photoelectric emission. it does not explain how the particle of the atom contribute significantly to the entire mass of an atom

7 0

4 years ago

A sample of 02 gas occupies 346 mL at 45°C and 1.50 atm. What is the volume of this O2 gas sample at STP? Enter your answer in t

sladkih [1.3K]

<u>Answer:</u> The volume of oxygen gas at STP is 446 mL

<u>Explanation:</u>

STP conditions are:

Pressure of the gas = 1 atm

Temperature of the gas = 273 K

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law. The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=1.50atm\\V_1=346mL\\T_1=45^oC=(45+273)K=318K\\P_2=1atm\\V_2=?\\T_2=273K$

Putting values in above equation, we get:

$\frac{1.50atm\times 346mL}{318K}=\frac{1atm\times V_2}{273K}\\\\V_2=446mL$

Hence, the volume of oxygen gas at STP is 446 mL

5 0

3 years ago

Read 2 more answers

Please help me, I’m stuck on this question

zubka84 [21]

Answer:

$\large \boxed{\text{0.0820 L$\cdot$atm$\cdot$K$^{-1}$mol}^{-1 }}$

Explanation:

To solve this problem, we can use the Ideal Gas Law:

pV = nRT

Data:

p = 3.00 atm

V = 17.4 L

n = 2.00 mol

T = 45 °C

Calculations:

1. Convert the temperature to kelvins

T = (45 + 273.15) K = 318.15 K

2. Calculate the value of R

$\begin{array}{rcl}pV & = & nRT\\\text{3.00 atm} \times \text{17.4 L} & = & \text{2.00 mol} \times R \times \text{318.15 K}\\\text{52.2 L$\cdot$atm} & = & 636.30R \text{ K$\cdot$mol}\\R & = & \dfrac{\text{52.2 L$\cdot$atm}}{636.30 \text{ K$\cdot$mol}}\\\\ & = & \textbf{0.0820 L$\cdot$atm$\cdot$K$^{-1}$mol}^{-1} \\\end{array}\\\text{The value of the gas constant R is $\large \boxed{\textbf{0.0820 L$\cdot$atm$\cdot$K$^{-1}$mol}^{-1 }}$}$

7 0

3 years ago

CuSO4 . 5H2O is dehydrated to form Copper (ii) sulfate. Is this a physical or chemical change? Explain.

Paraphin [41]

Answer:

It is a physical change.

Explanation:

• This is because when anhydrated copper (ii) sulfate is heated, the water evaporates to form anhydrous copper (ii) sulfate.

• evaporation is a physical change

$.$

3 0

3 years ago

Name the alkane that contains 18 hydrogen atoms

drek231 [11]

Answer:

Octadecane

Explanation:

.............

3 0

3 years ago