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3 years ago

7

How much is the pressure exerted at a point where a ball- pointed pen of area 1mm 2 is pushed against the paper with a force of

24 N

1 answer:

AURORKA [14]3 years ago

7 0

Answer:

Please find the attached pdf

Explanation:

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Which part of the manufacturing process involves heating and rolling blocks of steel into flat sheets and bars?

faltersainse [42]

A. Forming

Explanation:

Metal forming is a metallurgical process which involves heating and rolling blocks of steel into flat sheets and bars.

Metal forming is the process of working metals and utilizing its properties to form different shapes.

Metal forming is made possible by metallic bonds in metals.
The bulk of the physical properties of metals can be attributed to these bond types.
In metal forming, metals are shaped into different substances.
Metal forming preserves the mass of the metallic body and the shapes modified by force.

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Metals brainly.com/question/9053565

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8 0

3 years ago

A 1-meter-long wire consists of an inner copper core with a radius of 1.0 mm and an outer aluminum sheathe, which is 1.0 mm thic

Mazyrski [523]

Answer:

The total resistance of the wire is = $1.917\times10^{-3}$

Explanation:

Since the wires will both be in contact with the voltage source at the same time and the current flows along in their length-wise direction, the two wires will be considered to be in parallel.

Hence, for resistances in parallel, the total resistance, $R_{Total}$

$\frac{1}{R_{Total}} =\frac{1}{R_{cu} }+\frac{1}{R_{al}}$

Parameters given:

Length of wire = 1 m

Cross sectional area of copper $A_{cu}= \pi r^{2}= \pi \times (1\times 10^{-3} )^{2} =3.142\times10^{-6} m^{2}$

Cross sectional area of aluminium wire

$A_{al}= \pi( R^{2}-r^{2})\\\\ = \pi \times [ (2\times 10^{-3} )^{2}-(1\times 10^{-3} )^{2}] =9.42\times10^{-6} m^{2}\\$

Resistivity of copper $\rho _{cu}=1.7\times 10^{-8} \Omega .m$

Resistivity of Aluminium $\rho _{al}=2.8\times 10^{-8} \Omega .m$

Resistance of copper $R_{cu}= \frac{\rho_{cu} \times l}{A_{cu} } =\frac{1.7\times 10^{-8} \times 1}{3.142\times10^{-6} } =5.41\times 10^{-3}\Omega$

Resistance of aluminium $R_{al}= \frac{\rho_{al} \times l}{A_{al} } =\frac{2.8\times 10^{-8} \times 1}{9.42\times10^{-6} } =2.97\times 10^{-3}\Omega$

The total resistance of the wire can be obtained as follows;

$\frac{1}{R_{Total}} =\frac{1}{5.41\times10^{-3} }+\frac{1}{2.97\times10^{-3}}=521.52\frac{1}{\Omega}$

$R_{Total}= 1.917\times 10^{-3}\Omega$

∴ The total resistance of the wire = $1.917\times 10^{-3}\Omega$

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sineoko [7]

Answer:

When work is being done, the practie of labor is being performed. When work isn't being completed, this is a sign of procrastination.

Explanation:

In the answer.

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What can be found in a compost bin?

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D. all of the above

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Ian and Dane are twins. Ian loves art and music and work after school. Dane loves sports and would do anything to avoid having a

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2 years ago