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PIT_PIT [208]
3 years ago
8

It serves as the fuctional unit of the nervous system

Physics
2 answers:
serious [3.7K]3 years ago
6 0

Answer:

i would say the neuron

egoroff_w [7]3 years ago
5 0
The neuron is the functional unit of the nervous system.
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WILL GLADLY GIVE BRAINIEST FOR THIS EASY QUESTION
Alekssandra [29.7K]

The atomic number of Copper is 29.  So immediately we know that there are <em>29 protons </em>in the nucleus of each Copper atom, and <em>29 electrons</em> in the cloud surrounding the nucleus of each [neutral] Copper atom.

Copper has two stable isotopes ... ⁶³Copper and ⁶⁵Copper.  So if the Copper atom you're holding in your hand is not radioactive, then it has either (63-29)=<em>34 neutrons</em> or (65-29)=<em>36 neutrons</em> in its nucleus. (There's never a need to round the number of neutrons, because there's no such thing as a <em>part </em>of a neutron.)

4 0
3 years ago
Read 2 more answers
it takes 840s to walk completely around a circular track, moving at a speed of 1.20m/s? what is the radius of the track?
Tcecarenko [31]

Answer:

160.43 meters

Explanation:

T=(2*pi*r)/v

840=(2*pi*r)/1.2

1008=2*pi*r

504=pi*r

160.43=radius

6 0
3 years ago
Calculate the de Broglie wavelength of: a) A person running across the room (assume 180 kg at 1 m/s) b) A 5.0 MeV proton
solmaris [256]

Answer:

a

\lambda = 3.68 *10^{-36} \  m

b

\lambda_p = 1.28*10^{-14} \ m

Explanation:

From the question we are told that

   The mass of the person is  m =  180 \  kg

    The speed of the person is  v  =  1 \  m/s

    The energy of the proton is  E_ p =  5 MeV = 5 *10^{6} eV  = 5.0 *10^6 * 1.60 *10^{-19} = 8.0 *10^{-13} \  J

Generally the de Broglie wavelength is mathematically represented as

      \lambda = \frac{h}{m * v }

Here  h is the Planck constant with the value

      h = 6.62607015 * 10^{-34} J \cdot s

So  

     \lambda = \frac{6.62607015 * 10^{-34}}{ 180  * 1  }

=> \lambda = 3.68 *10^{-36} \  m

Generally the energy of the proton is mathematically represented as

         E_p =  \frac{1}{2}  *   m_p  *  v^2_p

Here m_p  is the mass of proton with value  m_p  =  1.67 *10^{-27} \  kg

=>     8.0*10^{-13} =  \frac{1}{2}  *   1.67 *10^{-27}  *  v^2

=>   v _p= \sqrt{\frac{8.0 *10^{-13}}{ 0.5 * 1.67 *10^{-27}} }

=>   v = 3.09529 *10^{7} \  m/s

So

        \lambda_p = \frac{h}{m_p * v_p }

so    \lambda_p = \frac{6.62607015 * 10^{-34}}{1.67 *10^{-27} * 3.09529 *10^{7} }

=>     \lambda_p = 1.28*10^{-14} \ m

     

5 0
3 years ago
What kind of acceleration occurs when an object speeds up?
Fantom [35]

Answer:

Postive Acceleration

Explanation:

3 0
3 years ago
Read 2 more answers
According to Freud, a person’s current perceptions and thoughts would be located at the __________ level. A. conscious B. noncon
Nikolay [14]

Answer:

A. conscious

Explanation:

8 0
3 years ago
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