The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
The last expression: (16-8)x2+4=8x6=48
Answer:
0 with multiplicity 3, 3 with multiplicity 1, and 6 with multiplicity 1.
Answer:
7
Step-by-step explanation:
first put them in order
5,6,6,8,9,9
now the ones that are in the middle are 6 and 8 so we find the average by adding them then dividing by 2
6+8=14/2=7