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2 years ago

Is Calcium oxide (CaO) covalent or ionic?

Chemistry

2 answers:

shusha [124]2 years ago

8 0

Answer:

ionic

Explanation:

Paul [167]2 years ago

6 0

Answer:

Calcium oxide （CaO）is ionic.

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Can you help me on this since im struggling on this since day 1

emmasim [6.3K]

Of Ok here is what I am thinking.

Simple replacement means when one element or compound moves out of another element and is replaced by this compound.

For example if you have A+BC ----- AC + B

Most of the time the one which is replaced is found on the right and the left one is going be only one element or compound.

Double replacement means when the two compounds exchange the positive and negative ions. Ok let see this example:

AB+ CD------- AD+ BC
this means if A have + sign and D has - sign they will share to form new compound the same is true for DC. Don't forget that all compounds are formed from positive and negative ions.

QUESTIONS
CUSO4 + NA2S---- CUS + Naso4[ double replacement]
KBR +Pb[CLO3]2------K[clo3]2 +PbBr [ double replacement]
I do not think these questions can be single replacement.
I hope this may helps you.

3 0

2 years ago

Ascorbic acid (H2C6H6O6; H2Asc for this problem), known as vitamin C, is a diprotic acid (Ka1= 1.0x10–5 and Ka2= 5x10–12) found

Igoryamba

Answer:

The concentrations are :

$[HAsc^-]=0.000702 M$

$[Asc^{2-}]=5.92\times 10^{-8} M$

The pH of the solution is 3.15.

Explanation:

$H_2Asc\rightleftharpoons HAs^-+H^+$ $K_{a1}=1.0\times 10^{-5}$

Initial

c 0 0

Equilibrium

c-x x x

$K_{a1}=\frac{[HAs^-][H^+]}{[H_2Asc]}$

$1.0\times 10^{-5}=\frac{x\times x}{(c-x)}$

$1.0\times 10^{-5}=\frac{x^2}{(0.050-x)}$

Solving for x:

x = 0.000702 M

$[HAsc^-]=0.000702 M$

$HAsc^-\rightleftharpoons As^{2-}+H^+$ $K_{a2}=5\times 10^{-12}$

Initially

x 0 0

At equilibrium ;

(x - y) y y

$K_{a2}=\frac{[As^{2-}][H^+]}{[HAsc^-]}$

$5\times 10^{-12}=\frac{y\times y}{(x-y)}$

$5\times 10^{-12}=\frac{y^2}{(x-y)}$

Putting value of x = 0.000702 M

$5\times 10^{-12}=\frac{y^2}{(0.000702 -y)}$

$y=5.92\times 10^{-8} M$

$[Asc^{2-}]=5.92\times 10^{-8} M$

Total concentration of $[H^+]=x+y=0.000702 M+5.92\times 10^{-8} M=7.0206\times 10^{-4} M$

The pH of the solution :

$pH=-\log[H^+]$

$pH=-\log[7.0206\times 10^{-4} M}=3.15$

7 0

2 years ago

If a reaction has a theoretical yield of 10.0 g and a student does the reaction and

lbvjy [14]

Answer:

78.4%

Explanation:

yield = actual/theoretical = 7.84/10 = 78.4%

6 0

2 years ago

Read 2 more answers

Using the brønsted theory, classify the compounds as either an acid or a base

Natali5045456 [20]

Answer:

all the below are ACIDS

Explanation:

1.HCOO- Formate

HCOO- is a conjugate base.

2.HNO3- Nitric Acid

Acid

3.CH3COOCH3: Methyl acetate

Acid

4. HCOOH: Formic Acid

Acid

Hope it helps..pls mark as brainliest!

8 0

2 years ago

How many moles are in 110 grams of nahco3

yuradex [85]

Molar mass NaHCO₃ = 23 + 1 + 12 + 16 x 3 = 84 g/mol

1 mole ---------- 84 g
? mole ---------- 110 g

moles NaHCO₃ = 110 . 1 / 84

moles NaHCO₃ = 110 / 84

= 1.309 moles

hope this helps!

4 0

2 years ago