Answer:
∆v = 61.0 m/s
θ = 305°
Explanation:
Given;
initial velocity u= 50.0 m/s angle 270°
Final velocity v = 35.0 m/s angle 180°
∆v = v - u ........1
Resolving into x and y axis;
For y axis
∆vy = vsin180 - usin270
∆vy = 0 - (-50) = 50 m/s
x axis;
∆vx = vcos180 - ucos270
∆vx = -35 - 0= -35m/s
Magnitude of ∆v;
∆v = √(-35^2 + 50^2)
∆v = 61.0 m/s
Direction;
Tanθ = ∆vy/∆vx
θ = taninverse (50/-35)
θ = -55°
θ = 360-55 = 305°
The goal of cognitive-behavioral therapy is BEST described as modifying the client's negative behavior and dysfunctional ways of thinking
What is cognitive-behavioral therapy ?
Talk therapy often used today is cognitive behavioural therapy (CBT) (psychotherapy). You engage in scheduled therapy sessions with a mental health professional (psychotherapist or therapist). To view difficult events more clearly and respond to them more effectively, CBT teaches you to become aware of false or negative thinking.
In order to assist people identify their most important goals and get through roadblocks, cognitive behavioral therapy (CBT) uses a time-sensitive, structured, present-oriented approach. The cognitive model, on which CBT is based, states that people's perceptions of situations have a stronger influence over their responses than the actual circumstances.
To know more about cognitive behavioral therapy use link below:
brainly.com/question/7773389
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Answer:
25.8 minutes
Explanation:
The time it takes for the journey if the current velocity is maintained:
T=144/48= 3 hours.
The time it takes for the journey if he increases his velocity to 56 km/hour:
144-56 = approx. 2.57 hours.
Time saved =.43*60=25.8 minutes
A. Units
the rest can be understand that he did not clarify
Answer:
vf = 30 m/s : (the magnitude of the velocity of the stone just before it hits the ground)
Explanation:
Because the stone moves with uniformly accelerated movement we apply the following formulas:
vf²=v₀²+2*g*h Formula (1)
Where:
h: displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
g: acceleration due to gravity in m/s²
Free fall of the stone
Data
v₀ = 10 m/s
vf = 30.0 m/s
g = 9,8 m/s²
We replace data in the formula (1) to calculate h:
vf²=v₀²+2*g*h
(30)² = (10)² + (2)(9.8)*h
(30)²- (10)²= (2)(9.8)*h
h =( (30)²- (10)²) /( 2)(9.8)
h = 40.816 m
Semiparabolic movement of the stone
Data
v₀x = 10 m/s
v₀y = 0 m/s
g = 9.8 m/s²
h= 40.816 m
We replace data in the formula (1) to calculate vfy :
vfy² = v₀y² + 2*g*h
vfy² = 0 + (2)(9.8)( 40.816)
