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Advocard [28]
3 years ago
6

Give a strong idea to protect , purify and the beautify of the Dal lake​

Physics
1 answer:
Sholpan [36]3 years ago
3 0

Answer:

Water in dal lake is test for any heavy metals and pollutant, sewage and drainage system are also monitored for the same.

Explanation:

  • Dal lake is located in Srinagar that is the state capital of Kashmir and is known for recreation and tourism purposes. The area covers about 18 km sq. and forms a part of natural wetlands.
  • The lake is prone to pollution and has recently undergone restoration measures. To address the problems of eutrophication algae and large-scale microplankton have been removed from the water.
  • The government of India has taken various measures to check the pollution by setting up a committee to monitor the proper use of allotted funds.
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A transformer has a primary coil with 106 turns and a secondary coil of 340 turns. The AC voltage across the primary coil has a
UkoKoshka [18]

To solve this problem it is necessary to apply the concepts related to transformers, that is to say passive electrical device that transfers electrical energy from one electrical circuit to one or more circuits.

From the mathematical definition we have that the relationship between the voltage of the first coil and the second coil is proportional to the number of loops of the first and second loop, that is:

\frac{V_s}{V_p} = \frac{N_s}{N_p}

Where

V_p =  input voltage on the primary coil.

V_s=input voltage on the secondary coil.

N_p=  number of turns of wire on the primary coil.

N_s = number of turns of wire on the secondary  coil.

Replacing our values we have:

V_p = 128V

N_p = 106

N_s = 340

Replacing,

\frac{V_s}{128} = \frac{340}{106}

V_s = 410.56V

From the same relations of number of turns and the voltage of the first and second coil we also have the relation of electricity and voltage whereby:

V_s I_s = V_p I_p

Where

I_p= Current Primary Coil

I_s = Current secundary Coil

Therefore:

I_s = \frac{V_p I_p}{V_s}

I_s = \frac{(128)(6)}{410.56}

I_s = 1.87 A

Therefore the maximum values for the secondary coil of the voltage is 410.56V and Current is 1.87A

5 0
3 years ago
6. Mass affects how fast an object falls.<br> True<br> False
dimulka [17.4K]

The statement: Mass affects how fast an object falls is true.

6 0
3 years ago
Read 2 more answers
A bird flying straight upward at 5 m/s drops a berry when it is 300 m above the ground. How fast is the berry going when it hits
Nikitich [7]

Answer:

v=77.62 m/s

Explanation:

Given that

h= - 300 m

speed of the bird ,u= 5 m/s

Lets take Speed of the berry when it hit the ground = v m/s

we know that ,if object is moving upward

v² = u² - 2 g h

u=Initial speed

v=Final speed

h=Height

Now by putting the values

v² = u² - 2 g h

v² = 5² - 2 x 10 x (-300)                ( take g = 10 m/s²)

v² =25 + 20 x 300

v² ==25 + 6000

v² =6025

v=77.62 m/s

Therefore the final speed of the berry will be 77.62 m/s.

5 0
3 years ago
What is the period? Blank seconds.
FromTheMoon [43]

Answer:

Period refers to the time for something to happen and is measured in seconds/cycle

8 0
3 years ago
On a straight, level, two-lane road, two cars moving in opposite directions approach and pass each other. Car A is in the eastbo
ludmilkaskok [199]

Answer:

a) 42 m/s, positive direction (to the east), b) 42 m/s, negative direction (to the west).

Explanation:

a) Let consider that Car A is moving at positive direction. Then, the relative velocity of Car A as seen by the driver of Car B is:

\vec v_{A/B} = \vec v_{A} - \vec v_{B}\\\vec v_{A/B} = 11 \frac{m}{s} \cdot i + 31 \frac{m}{s} \cdot i\\\vec v_{A/B} = 42 \frac{m}{s} \cdot i

42 m/s, positive direction (to the east).

b) The relative velocity of Car B as seen by the drive of Car A is:

\vec v_{B/A} = \vec v_{B} - \vec v_{A}\\\vec v_{B/A} = -31 \frac{m}{s} \cdot i - 11 \frac{m}{s} \cdot i\\\vec v_{B/A} = - 42 \frac{m}{s} \cdot i

42 m/s, negative direction (to the west).

5 0
3 years ago
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