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Fofino [41]
2 years ago
8

When a electric current is passed threw water during electrolysis, 2 gases are formed. 1 gas has a boiling point of -183°C and t

he other has a boiling point of -253°C. Has a physical or a chemical change occurred? Explain please.
Physics
1 answer:
Keith_Richards [23]2 years ago
8 0

Answer:

Sorrry so very hard

Ok hahaha

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Experiment: Limestone
White raven [17]
When these bonds are destroyed, a reaction occurs. ... Vinegar reacting with limestone breaks the bonds of calcium carbonate and acetic acid.
7 0
3 years ago
Which of the following is a vector quantity?
gizmo_the_mogwai [7]

Answer:

B. 30 m down

Explanation:

In physics we have two types of quantities:

- Scalar quantity: it is a quantity which only has a magnitude (e.g: mass and time are scalar quantities, since they only have a magnitude)

- Vector quantity: it is a quantity which has both a magnitude and a direction (e.g: velocity is a vector quantity, since it has a magnitude (the speed) and a direction)

In this problem, we have:

A. 100 ounces of water  --> scalar (this is a volume, which has only a magnitude)

B. 30 m down  --> vector (this is a displacement, which has both a magnitude (30 m) and a direction (down)

C. 88 mi/s  --> scalar (this is a speed, which has only a magnitude)

D. 45 gallons in a bucket --> scalar (this is a volume, which has only a magnitude)

So, the correct option is B.

4 0
3 years ago
Given two vectors A=4i^+3j^ and vector<br> B=5i^-2j^.find the magnitude of each vector
Flura [38]

Answer:

<em>Magnitude of A=5</em>

<em>Magnitude of B=5.39</em>

Explanation:

<u>The magnitude of Vectors in Rectangular Form</u>

Given a vector v in its rectangular form:

\mathbf{v}=x\hat i+y\hat j

The magnitude of v is:

\mid\mid\mathbf{v}\mid \mid=\sqrt{x^2+y^2}

We are given the vectors

\mathbf{A}=4\hat i+3\hat j

\mathbf{B}=5\hat i-2\hat j

Their magnitudes are:

\mid\mid\mathbf{A}\mid \mid=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}

\mid\mid\mathbf{A}\mid \mid=5

\mid\mid\mathbf{B}\mid \mid=\sqrt{5^2+(-2)^2}=\sqrt{25+4}=\sqrt{29}

\mid\mid\mathbf{B}\mid \mid=\sqrt{29}=5.39

4 0
3 years ago
A pressurized tank of water has a 10-cm-diameter orifice at the bottom, where water discharges to the atmosphere. The water leve
Alex Ar [27]

Answer:

The velocity is 18.68m/s

Explanation:

Bernoulli's equation is applicable for stream line flow of a fluid. The flow must be steady and uniform flow. The Bernoulli's equation between inlet and outlet is written as:

P1/pg + V1/2g + Z1 = P2/pg + V2^2 + Z2

Where V1 and V2 are velocity of fluid at point 1 and 2b. The diameter of the tank too will be larger than that of the nozzle. Hence the velocity at point 1 will be 0.V1= 0

Substituting the values in to the equation

250 ×10^3/1000g + 0/g + 2.5 = 100×10^3/1000g + V2^2/2g + 0

250 + 2.5g = 100 + V2^2/2

250 + (2.5 × 9.8) = 100 V2^2/2

250 + 23.525- 100 = V2^2/2

174.525 = V2^2/2

Cross multiply

174.525 × 2 = V2^2

V2 = 349.05

V2 = Sqrt(349.05)

V2 = 18.68m/s

6 0
3 years ago
Read 2 more answers
17V:=192)
BartSMP [9]

Answer:

THAT loooks hard123 -

Explanation:

v hard..... 1234=123

vhemistryyyy

4 0
2 years ago
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