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maw [93]
3 years ago
15

Which one of the following is an example of an indicator?

Physics
1 answer:
pshichka [43]3 years ago
5 0
C: Litmus Paper. Red litmus paper turns blue in acids; blue litmus paper turns red in bases
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A 1.0 kg rock moving at 8.4 m/s will have ______ of kinetic energy
BlackZzzverrR [31]
K.E=1/2mv^2 K.E=1/2multiply1multiply8^2=32joules
4 0
3 years ago
What is the weight of a 48kg rock?
IrinaK [193]

Answer:

48kg

Explanation:

4 0
3 years ago
The largest watermelon ever grown had a mass of 118 kg. Suppose this watermelon were exhibited on a platform 5.00 m above the gr
WINSTONCH [101]

Answer: height = 3.98m

Explanation: by placing the watermelon at a height above the ground, it has a potential energy of the formulae

p = mgh

p = potential energy = 4.61kJ = 4610J

m = mass of watermelon = 118 kg

g = acceleration due gravity = 9.8 m/s²

4610 = 118 * 9.8 * h

h = 4610/ 118 * 9.8

h = 4610/ 1156.4

h = 3.98m

6 0
3 years ago
Unpolarized light of intensity I0 = 950 W/m2 is incident upon two polarizers. The first has its polarizing axis vertical, and th
Ket [755]

Answer:

Intensity of the light (first polarizer) (I₁) = 425 W/m²

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

Explanation:

Given:

Unpolarized light of intensity (I₀) = 950 W/m²

θ = 65°

Find:

a. Intensity of the light (first polarizer)

b. Intensity of the light (second polarizer)

Computation:

a. Intensity of the light (first polarizer)

Intensity of the light (first polarizer) (I₁) = I₀ / 2

Intensity of the light (first polarizer) (I₁) = 950 / 2

Intensity of the light (first polarizer) (I₁) = 425 W/m²

b. Intensity of the light (second polarizer)

Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ

Intensity of the light (second polarizer) (I₂) = (425)(0.1786)

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

5 0
3 years ago
1. A car starting from rest accelerates uniformly at 3
amid [387]

The car's final speed in  m/s after the acceleration is 30.

<u />

<u>Given the following data:</u>

  • Initial velocity, U = 0 m/s (since the cars starts from rest)
  • Time, t = 10 seconds
  • Acceleration, a = 3 meter per seconds square.

To find the car's final speed in  m/s after the acceleration, we would use the first equation of motion;

Mathematically, the first equation of motion is given by the formula;

V = U + at\\\\V = 0 + 3(10)

<em>Final speed, V </em><em>=</em><em> 30 m/s</em>

Therefore, the car's final speed in  m/s after the acceleration is 30.

Read more: brainly.com/question/8898885

5 0
3 years ago
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