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harina [27]
3 years ago
14

What is the difference between muscular endurance and muscular strength? A B or C

Physics
1 answer:
Galina-37 [17]3 years ago
7 0

Answer:

Muscular endurance is how many times you can move a weight without getting tired.

Muscular strength is the amount force you can put out.

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to lift a load to roof, you apply 21 n of force to a pulley. the pulley applies 21 n of force to the load. what is the mechanica
MariettaO [177]

Answer:

The mechanical advantage of the pulley is 1.

Explanation:

The mechanical advantage of the pulley is given as

MA=\frac{F}{f}

Here, MA is represent for the mechanical advantage of the pulley, F is load for lift and f applied force.

Given F =21 N and f= 21 N.

Substitute the given values, we get

MA=\frac{21N}{21N}

MA = 1.

Thus, the mechanical advantage of the pulley is 1.

7 0
4 years ago
What is the kinetic energy in Joules of a 1,500kg car traveling at 75mph?What is the kinetic energy in Joules of a 1,500kg car t
Sergio039 [100]

Answer: 2812500 joules

Explanation:

Mass of car = 1500kg

Velocity of car = 75mph

Kinetic energy = ?

Recall that kinetic energy is the energy possessed by a moving object, and it depends on its mass M and velocity, V

Thus, Kinetic energy = 1/2 x mv^2

= 1/2 x 1000kg x (75mph)^2

= 0.5 x 1000kg x (75mph)^2

= 500 x 5625

= 2812500 joules

Thus, the car travels with a kinetic energy of 2812500 joules

5 0
3 years ago
A student put her ear on one end of a long piece of lead. She asked her friend to
Ludmilka [50]

1) The length of the lead is 1700 m

2) The frequency of the wave is 400 Hz

Explanation:

1)

The wave in this problem is a sound wave, which is produced by the vibrations of the particles of air. It is a type of longitudinal wave (which means that the vibrations occur back-and-forth along the direction of propagation of the wave).

The speed of a sound wave in air is approximately

v = 340 m/s

In this problem, the sound wave is heard after a time of

t = 5 s

after the shot. Therefore, the distance travelled by the wave in this time (and therefore, the length of the lead) is

d=vt=(340)(5)=1700 m

2)

The frequency of a wave is the number of complete cycles made by the wave in one second.

For the wave in this problem, we are told that the wave has 2000 whole wavelengths in 5 seconds: this means that the wave completes 2000 cycles in 5 seconds. Therefore, we can find the frequency by setting up the following proportion:

\frac{2000}{5}=\frac{x}{1}

where x is the number of cycles made in 1 second. Solving for x,

x=\frac{2000\cdot 1}{5}=400 s^{-1}

Therefore, the frequency of the wave is

f=400 Hz

Learn more about waves and frequency:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

7 0
4 years ago
a cepheid variable star is a star whose brightness alternately increases and decreases. suppose that cephei joe is a star for wh
MrRissso [65]

After one day, the rate of increase in Delta Cephei's brightness is;0.46

We are informed that the function has been used to model the brightness of the star known as Delta Cephei at time t, where t is expressed in days;

B(t)=4.0+3.5 sin(2πt/5.4)

Simply said, in order to determine the rate of increase, we must determine the derivative of the function that provides

B'(t)=(2π/5.4)×0.35 cos(2πt/5.4)

Currently, at t = 1, we have;

B'(1)=(2π/5.4)×0.35 cos(2π*1/5.4)

Now that the angle in the bracket is expressed in radians, we can use a radians calculator to determine its cosine, giving us the following results:

B'(1)=(2π/5.4)×0.3961

B'(1)≈0.46

To know more about:

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7 0
1 year ago
Question 2 of 10
Firdavs [7]
I think its a im not sure
8 0
3 years ago
Read 2 more answers
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