Answer:
at the Equator
Explanation:
The four seasons are determined by four main positions in the Earth's orbit in its turn around the Sun (ecliptic plane), which are called solstices and equinoxes: winter solstice (Capricorn point, December 22), spring equinox (Aries point, around March 21-22), summer solstice (Cancer point, June 21) and autumn equinox (Libra point, around September 22-23).
In the equinoxes, the axis of rotation of the Earth is perpendicular to the sun's rays, which fall vertically over the equator. In solstices, the axis is inclined 23.5º, so that the sun's rays fall vertically on the Tropic of Cancer (summer in the northern hemisphere) or Capricorn (summer in the southern hemisphere).
When falling vertically on Ecuador, it generates a greater impact on the surface of the Tierre reaching a greater amount of energy and therefore UV rays.
Answer:
The kinetic energy increases 4 times
Explanation:
Given,
The mass of the car, m = 1500 Kg
The speed of the car doubles from 50 Km/h to 100 Km/h
The kinetic energy at 50 Km/h
K.E = ½mv²
= ½ x 1500 x 50²
= 1875000 J
The kinetic energy of the car at 100 Km/h
K.E = ½mv²
= ½ x 1500 x 100²
= 7500000 J
Hence, the final K.E is 4 times the initial K.E
J.J. Thomson's experiments provided evidence that an atom B.contains negatively charged particles.
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Answer:
Substances that enhance the flow of current are called conductors
Substances that inhibit the flow of current are known as insulators
Substances that neither conduct nor inhibit are called semiconductors
Explanation:
- Substances that enhance the flow of current are called conductors because they allow electrical charges to pass through them.
- Substances that inhibit the flow of current are known as insulators because they prevent the flow of electrical charges through them.
- Substances that neither conduct nor inhibit flow of current as well are called semiconductors. These substances although they cannot conduct of prevent the flow of current, in certain conditions they can be made to conduct and reversed as well.
Answer:
(a) α = -0.16 rad/s²
(b) t = 33.2 s
Explanation:
(a)
Applying 3rd equation of motion on the circular motion of the tire:
2αθ = ωf² - ωi²
where,
α = angular acceleration = ?
ωf = final angular velocity = 0 rad/s (tire finally stops)
ωi = initial angular velocity = 5.45 rad/s
θ = Angular Displacement = (14.4 rev)(2π rad/1 rev) = 28.8π rad
Therefore,
2(α)(28.8π rad) = (0 rad/s)² - (5.45 rad/s)²
α = -(29.7 rad²/s²)/(57.6π rad)
<u>α = -0.16 rad/s²</u>
<u>Negative sign shows deceleration</u>
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(b)
Now, we apply 1st equation of motion:
ωf = ωi + αt
0 rad/s = 5.45 rad/s + (-0.16 rad/s²)t
t = (5.45 rad/s)/(0.16 rad/s²)
<u>t = 33.2 s</u>
