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Vlada [557]
3 years ago
5

If an ocean has a wavelength of 2 m and a frequency of 1 wave/s then it's speed is ___ m/s.

Physics
1 answer:
scoundrel [369]3 years ago
7 0
V = f x lamda

Wave speed = frequency x wavelength
2x1 = 2 so wave speed = 2m/s

Let me know if you have any questions
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A 3.00 x 10^2-W electric immersion heater is
andre [41]

Answer

t = 367.77 s = 6.13 min

Explanation:

According to the law of conservation of energy:

Heat\ Supplied\ By \ Heater = Heat\ Absorbed\ by\ Glass + Heat\ Absorbed\ by\ Water\\Pt = m_gC_g\Delta T_g + m_wC_w\Delta T_w\\

where,

P = Electric Power of Heater =  300 W

t = time required = ?

m_g = mass of glass = 300 g = 0.3 kg

m_w = mass of water = 250 g = 0.25 kg

C_g = speicific heat of glass = 840 J/kg.°C

C_w =  specific heatof water = 4184 J/kg.°C

ΔT_g = ΔT_w = Change in Temperature of Glass and water = 100°C - 15°C

ΔT_g = ΔT_w = 85°C

Therefore,

(300\ W)(t) = (0.3\ kg)(840\ J/kg.^oC)(85^oC)+(0.25\ kg)(4184\ J/kg.^oC)(85^oC)\\

<u>t = 367.77 s = 6.13 min</u>

8 0
3 years ago
A wire is wrapped around a piece of iron, and then electricity is run through the wire. What happens to the iron?
katrin [286]
Search Results<span>By simply wrapping wire that has an electrical current running through it around a nail, you can make an electromagnet. When the electric current moves through a wire, it makes a magnetic field. ... You can make a temporary magnet by stroking apiece of iron or steel (such as a needle) along with a permanent magnet.

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7 0
3 years ago
How much heat is needed to raise the temperature of 7g of Water by 20° C
beks73 [17]

the answer to your question is 10.5 kJ

6 0
3 years ago
A 500 kg object is hanging from a spring attached to the ceiling. If the spring constant in the spring is 900 N/kg, how far does
My name is Ann [436]

We are given that a 500 kg object is hanging from a spring. To determine the amount the spring is stretched we will use Hook's law, which states the following:

F=kx

Where:

\begin{gathered} F=\text{ force} \\ k=\text{ spring constant} \\ x=\text{ distance stretched} \end{gathered}

Since the object is hanging the only force acting on the spring is the weight of the object. The weight of the object is:

F_g=mg

Where:

\begin{gathered} m=\text{ mass} \\ g=\text{ acceleration of gravity} \end{gathered}

Plugging in the values we get:

F_g=(500\operatorname{kg})(9.8\frac{m}{s^2})

Solving the operations:

F_g=4900N

Now we solve for "x" from Hook's law by dividing both sides by "k":

\frac{F}{k}=x

Now we plug in the known values:

\frac{4900N}{900\frac{N}{m}}=x

Solving the operations:

5.4m=x

Therefore, the spring is stretched by 5.4 meters.

7 0
1 year ago
Two point charges, initially 2 cm apart, are moved to a distance of 10 cm apart. By what factor does the resulting electric forc
choli [55]

Answer: The correct answer is C.

2/10 is simplified to 1/5, that is the factor that changes.

5 0
3 years ago
Read 2 more answers
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