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svp [43]
3 years ago
10

A long straight wire carries a current I. If the magnetic field at a distance d from the wire has a magnitude B, what is the mag

nitude of the magnetic field at a distance 2d from the wire
Physics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

Explanation:

As the field of current wire passing through the loop is same in direction (normally inward) but not uniform in magnitude.

So, we will use integtation method for finding the flux.

The same flux through a thin reactangular strip of length l and with dx, is given by

dϕB=Bx.dS=B(x)dScos180∘.

Magnetic field due to a long straight wire carrying current I is given by B=μ0I2πx, and area, dS=l×dx.

∴ ϕB=∫dϕB=−∫μ02πIlx.dx=−μ02πIl[logex]x=a+lx=a

=−μ02π.Ill

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Two sound waves (speed 343 m/s) have different wavelengths. The first has a wavelength of 5.72 m, and the second a wavelength of
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Answer:

The beat frequency is 30 Hz

Explanation:

Given;

velocity of the two sound waves, v = 343 m/s

wavelength of the first wave, λ₁ = 5.72 m

wavelength of the second wave, λ₂ = 11.44 m

The frequency of the first wave is calculated as follows;

F₁ = v/λ₁

F₁ = 343 / 5.72

F₁ = 59.97 HZ

The frequency of the second wave is calculated as follows;

F₂ = v/λ₂

F₂ = 343 / 11.44

F₂ = 29.98 Hz

The beat frequency is calculated as;

Fb = F₁ - F₂

Fb =  59.97 HZ - 29.98 Hz

Fb = 30 Hz

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Twenty grams of a solid at 70°C is place in 100 grams of a fluid at 20°C. Thermal equilibrium is reached at 30°C.
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Answer:

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Explanation:

This problem is based on the conservation of energy and the concept of thermal equilibrium

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