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It is represented as: h =
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Answer:
Probability of finding girls given that only English students attend the subject =33/59
Step-by-step explanation:
Given that during English lesson, there is no other lesson ongoing. The probability of getting girls in that class only will be equivalent to 33/59 since we expect a total of 59 students out of which 33 will be girls. Similarly, in a Maths class given that only Maths students attend the class, probability of having a girl is 29/61 since out of all students, only 29 prefer Maths and the total class attendance is 61
Answer:
B
Step-by-step explanation:
The answer is B
Using the normal distribution, we have that:
The percentage of men who meet the height requirement is 3.06%. This suggests that the majority of employees at the park are females.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation of men's heights are given as follows:
.
The proportion of men who meet the height requirement is is the <u>p-value of Z when X = 62 subtracted by the p-value of Z when X = 55</u>, hence:
X = 62:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{62 - 69.3}{3.9}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B62%20-%2069.3%7D%7B3.9%7D)
Z = -1.87
Z = -1.87 has a p-value of 0.0307.
X = 55:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{55 - 69.3}{3.9}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B55%20-%2069.3%7D%7B3.9%7D)
Z = -3.67
Z = -3.67 has a p-value of 0.0001.
0.0307 - 0.0001 = 0.0306 = 3.06%.
The percentage of men who meet the height requirement is 3.06%. This suggests that the majority of employees at the park are females.
More can be learned about the normal distribution at brainly.com/question/4079902
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<span>Standard deviation is the square root of variance. Variance is always a non-negative number, since you can't take the square root of a negative number. So neither can be negative </span>