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stellarik [79]
3 years ago
15

One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large

enough to be detected by radar, but there are far greater numbers of very small objects, such as flakes of paint. The force exerted by a 0.100-mg chip of paint that strikes a spacecraft window at a relative speed of 4.00 x 103 m/s, given the collision lasts 6.00 x 10-8 s is Fill input: x 106 N.
Physics
1 answer:
Citrus2011 [14]3 years ago
7 0

Answer:

The correct answer is "6666.67 N".

Explanation:

The given values are:

Mass,

m = 0.100

Relative speed,

v = 4.00 x 10³

time,

t = 6.00 x 10⁻⁸

As we know,

⇒  F=m(\frac{\Delta v}{\Delta t} )

On substituting the given values, we get

⇒      =0.100\times 10^{-6}(\frac{4\times 10^3}{6\times 10^{-8}} )

⇒      =6666.67 \ N

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An RC circuit is connected across an ideal DC voltage source through an open switch. The switch is closed at time t = 0 s. Which
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e)

Explanation:

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Someone places a chocolate bar near a working radar set that is used to locate ships and airplanes. Which best describes what is
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Amir pitches a baseball at an initial height of 6 feet with a velocity of 73 feet per second. this can be represented by the fun
Romashka [77]

The values of t are <u>4.643 second</u> for the function H(t)=-16t^2+73t+6

What is batter misses?

An out in baseball happens when the umpire declares a batter or baserunner out. A hitter or runner who is out is no longer able to score runs and must go back to the dugout until their subsequent turn at bat. The batting team's turn is over after three outs are recorded in a half-inning.

In order to signal an out, umpires typically make a fist with one hand and then flex that arm, either upward on pop flies or forward on regular plays at first base. To indicate a called strikeout, home plate umpires frequently use a "punch-out" action.When a batter is struck by a pitched ball without making a swing at it, it is referred to as a hit-by-pitch. He consequently gets first base.

We have been given that

s = 6 feet

v = 73 feet per second

Substituting these values in the formula H(t)=-16t^2+vt+s

H(t)=-16t^2+73t+6

When the ball hits the ground, the height becomes zero. Thus, H(t)=0

-16t^2+73t+6=0

We solve the equation using quadratic formula x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

Substituting the values a=-16, b= 73, c=6

t_{1,2}=\frac{-73 \pm \sqrt{(73)^2-4(-16)(6)}}{2(-16)}\\\Rightarrow t_{1,2}=\frac{-73 \pm \sqrt{5713}}{2(-16)}\\\Rightarrow t_{1,2}=-0.081, 4.643

Learn more about the batter misses with the help of the given link:

brainly.com/question/19475098

#SPJ4

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