Explanation:
the answer is in the above image
Since the molecular weight of water is about 18 g/mol, you have about 1 mol of water. So, now we know that it takes approximately 46.2 kJ of heat energy to warm 18.02g of water from 25C to 100C and then to vaporize it into steam. Hopefully this helped!
Explanation:
Answer:
Density=1.006 g/cm^3 .
Detailed explanation in screenshot attached below
Explanation:
Answer:
[NO] = 1.72 x 10⁻³ M.
Explanation:
<em>2NO(g) ⇌ N₂(g)+O₂(g),</em>
Kc = [N₂][O₂] / [NO]².
- At initial time: [NO] = 0.171 M, [N₂] = [O₂] = 0.0 M.
- At equilibrium: [NO] = 0.171 M - 2x , [N₂] = [O₂] = x M.
∵ Kc = [N₂][O₂] / [NO]².
∴ 2400 = x² / (0.171 - 2x)² .
<u><em>Taking the aquare root for both sides:</em></u>
√(2400) = x / (0.171 - 2x)
48.99 = x / (0.171 - 2x)
48.99 (0.171 - 2x) = x
8.377 - 97.98 x = x
8.377 = 98.98 x.
∴ x = 8.464 x 10⁻².
<em>∴ [NO] = 0.171 - 2(8.464 x 10⁻²) = 1.72 x 10⁻³ M. </em>
<em>∴ [N₂] = [O₂] = x = 8.464 x 10⁻² M.</em>
