Estimate ΔG°rxn for the following reaction at 449.0 K. CH2O(g) + 2 H2(g) → CH4(g) + H2O(g) ΔH°= -94.9 kJ; ΔS°= -224.2 J/K
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The maximum amount of produced during the experiment can be find out by knowing the Limiting Reagent.
Here, The maximum amount of produced during the experiment is 400 grams
The limiting reagent (or limiting reactant or limiting agent) in a chemical reaction is a reactant that is totally consumed when the chemical reaction is stopped.
Now, According to the question,
Given ;
Number of moles of - 4 moles
Number of moles of NaCl - 9 moles
To Find - Maximum amount of produced during the reaction.
Solution ;
complete reaction ;
+ 3NaCl -->
+
To find the maximum amount of produced during the reaction,
we need to find the limiting reagent.
Mole ratio = 4/1 = 4
Mole ratio NaCl = 9/3 = 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of
9 moles of NaCl will produce = 1/3 x 9 = 3 moles.
Weight of = 3 x 133.34 = 400 grams
Thus, 400 grams of is the maximum amount of
produced during the experiment.
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