Answer:
(a) The proportion of dry air bypassing the unit is 14.3%.
(b) The mass of water removed is 1.2 kg per 100 kg of dry air.
Explanation:
We can express the proportion of air that goes trough the air conditioning unit as
and the proportion of air that is by-passed as
, being
.
The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

Replacing the first equation in the second one we have

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.
It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.
The water removed of every 100 kg of dry air is

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).
100 * 0.012 = 1.2 kgW
Explanation:
CO2 is called as gas because it exist in single thermodynamics state i.e CO exist in gases state only at room temperature.
Answer:
1.
Explanation:
Let's start with the hydrogen. If we have 4 grams of hydrogen, it would be enough for 4 * 9 = 36 grams of water. Well, that can't be possible ...
4 votes
Reaction equation:
K₂CrO₄(aq) + PbCl₂(aq) → 2KCl(aq) + PbCrO₄(s)
Concentration = moles / Liter
moles(K₂CrO₄) = 3 x 0.025
= 0.075
By the equation, we see that the molar ratio of
K₂CrO₄ : PbCrO₄ is
1 : 1
moles(PbCrO₄) = 0.075
mass = moles x Mr
mass = 0.075 x (207 + 52 + 16 x 4)
mass = 24.2 grams