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mixer [17]
3 years ago
13

Consider the reaction below. If you start with 2.00 moles of C3H8 (propane) and 2.00 moles of O2, how many moles of carbon dioxi

de can be produced? C3H8(g) + 5O2(g) 3CO2(g) + 4H2O(g). A) 8.00. B) 1.20. C) 6.00. D) 2.00.
Chemistry
1 answer:
Vladimir79 [104]3 years ago
5 0
From the balanced chemical reaction, the ratio of moles of propane to moles CO2 produced is 1/3. Given 2 moles of propane, 6 moles of CO2 is produced. Further, the ratio of moles of O2 to moles of CO2 produced is 5/3. Given 2 moles of oxygen, 1.2 moles of CO2 is produced. We take the smaller amount of CO2 as the answer. Thus, the answer is letter B. 1.2 moles
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Which characteristic makes legumes a good food source for food-insecure<br> populations?
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Legumes are much easier to grow than other plants, and are more adaptable.

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3 years ago
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Calculate the number of miles of magnesium,chlorine, and oxygen atoms in 5.00 moles of magnesium perchlorate
Zigmanuir [339]

Answer:

5.00 mol Mg

10.0 mol Cl

40.0 mol O

Explanation:

Step 1: Given data

Moles of Mg(ClO₄)₂: 5.00 mol

Step 2: Calculate the number of moles of Mg

The molar ratio of Mg(ClO₄)₂ to Mg is 1:1.

5.00 mol Mg(ClO₄)₂ × 1 mol Mg/1 mol Mg(ClO₄)₂ = 5.00 mol Mg

Step 3: Calculate the number of moles of Cl

The molar ratio of Mg(ClO₄)₂ to Cl is 1:2.

5.00 mol Mg(ClO₄)₂ × 2 mol Cl/1 mol Mg(ClO₄)₂ = 10.0 mol Cl

Step 4: Calculate the number of moles of O

The molar ratio of Mg(ClO₄)₂ to Cl is 1:8.

5.00 mol Mg(ClO₄)₂ × 8 mol O/1 mol Mg(ClO₄)₂ = 40.0 mol O

4 0
3 years ago
What refers to the body’s inability to maintain a stable internal environment.
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Define the difference between an atom, ion, and isotope.
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Determine the concentration of hydronium and hydroxide ions in a solution that has a pH of 1.6.
Veronika [31]

Answer:

The answer to your question is [H₃O⁺] = 0.025   [OH⁻] = 3.98 x 10⁻¹³

Explanation:

Data

[H⁺] = ?

[OH⁻] = ?

pH = 1.6

Process

Use the pH formula to calculate the [H₃O⁺], then calculate the pOH and with this value, calculate the [OH⁻].

pH formula

pH = -log[H₃O⁺]

-Substitution

1.6 = -log[H₃O⁺]

-Simplification

[H₃O⁺] = antilog (-1,6)

-Result

[H₃O⁺] = 0.025

-Calculate the pOH

pOH = 14 - pH

-Substitution

pOH = 14 - 1.6

-Result

pOH = 12.4

-Calculate the [OH⁻]

12.4 = -log[OH⁻]

-Simplification

[OH⁻] = antilog(-12.4)

-Result

[OH⁻] = 3.98 x 10⁻¹³

5 0
3 years ago
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