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mario62 [17]
3 years ago
14

Why do atoms like carbon and nitrogen not like to make ions, while sodium and chlorine do?

Physics
2 answers:
Daniel [21]3 years ago
5 0

<u>Explanation:</u>

This can be very well explained with the help of reactivity.

Reactivity of an element is defined as the tendency to loose or gain electrons.

Sodium is an element belonging to group 1 and is considered as a metal. This element can easily loose electrons and hence is considered as reactive element. This element tends to form positive ions.

Chlorine is an element belonging to Group 17 and is considered as a non-metal. This element can easily gain electrons and hence is considered as a reactive element. This element tends to form negative ions.

Carbon and nitrogen belong to group 14 and group 15 respectively. They are not very reactive because they can't loose or gain electrons easily. Carbon tends to form covalent bonds by sharing of electrons. Nitrogen very rarely forms ionic compounds.

This is the reason why carbon and nitrogen does not form ions but sodium and chlorine forms ions.

krok68 [10]3 years ago
3 0
Atoms like carbon and nitrogen do not form ions because the electronegativity of these atoms are not that high nor very low which means electrons are fairly stable in the atom. While chlorine has very high electronegativity and for sodium very low, atoms tend to receive or release electrons. 
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An ore sample weighs 17.50 N in air. When the sample is suspended by a light cord and totally immersed in water, the tension in
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<h3>Total volume of the sample</h3>

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That's also equal to the weight (weight, m \cdot g) of water that the object displaces. To find the mass of water displaced from its weight, divide weight with g.

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Assume that the density of water is \rho(\text{water}) = \rm  1.000\times 10^{3}\; kg \cdot m^{-3}. To the volume of water displaced from its mass, divide mass with density \rho(\text{water}).

\displaystyle V(\text{water displaced}) = \frac{m}{\rho} = \rm \frac{0.642\; kg}{1.000\times 10^{3}\; kg \cdot m^{-3}} \approx 6.42201 \times 10^{-4}\; m^{3}.

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V(\text{sample}) = V(\text{water displaced}) \approx \rm 6.422\times 10^{-4}\; m^{3}.

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Average density is equal to mass over volume.

To find the mass of the sample from its weight, divide with g.

\displaystyle m = \frac{m \cdot g}{g} = \rm \frac{17.50\; N}{9.81\; N \cdot kg^{-1}} \approx 1.78389 \; kg.

The volume of the sample is found in the previous part.

Divide mass with volume to find the average density.

\displaystyle \rho(\text{sample, average}) = \frac{m}{V} = \rm \frac{1.78389\; kg}{6.42201 \times 10^{-4}\; m^{3}} \approx 2.778\; kg \cdot m^{-3}.

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