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mario62 [17]
3 years ago
14

Why do atoms like carbon and nitrogen not like to make ions, while sodium and chlorine do?

Physics
2 answers:
Daniel [21]3 years ago
5 0

<u>Explanation:</u>

This can be very well explained with the help of reactivity.

Reactivity of an element is defined as the tendency to loose or gain electrons.

Sodium is an element belonging to group 1 and is considered as a metal. This element can easily loose electrons and hence is considered as reactive element. This element tends to form positive ions.

Chlorine is an element belonging to Group 17 and is considered as a non-metal. This element can easily gain electrons and hence is considered as a reactive element. This element tends to form negative ions.

Carbon and nitrogen belong to group 14 and group 15 respectively. They are not very reactive because they can't loose or gain electrons easily. Carbon tends to form covalent bonds by sharing of electrons. Nitrogen very rarely forms ionic compounds.

This is the reason why carbon and nitrogen does not form ions but sodium and chlorine forms ions.

krok68 [10]3 years ago
3 0
Atoms like carbon and nitrogen do not form ions because the electronegativity of these atoms are not that high nor very low which means electrons are fairly stable in the atom. While chlorine has very high electronegativity and for sodium very low, atoms tend to receive or release electrons. 
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A daring stunt woman sitting on a tree limb wishes to drop vertically onto a horse gallop ing under the tree. The constant speed
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Answer:

0.67 seconds

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Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow 2.23=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{2.23\times 2}{9.8}}\\\Rightarrow t=0.67\ s

Time taken by the stunt woman to drop to the saddle is 0.67 seconds which is the time she will stay in the air.

Speed of the horse = 12.8 m/s

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3 0
3 years ago
1 A 75-g ball is projected from a height of 1.6 m with a horizontal velocity of 2 m/s and bounces from a 400-g smooth plate supp
Tanzania [10]

Answer with explanation:

We are given that  

Mass of ball,m_1=75 g=\frac{75}{1000}=0075kg

1 kg=1000 g

Height,h_1=1.6 m

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Horizontal velocity,v_x=2 m/s

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Velocity before impact=u_1=\sqrt{2gh_1}=\sqrt{2\times 9.8\times 1.6}=5.6m/s

Where g=9.8 m/s^2

Velocity after impact,v_1=\sqrt{2gh_2}=\sqrt{2\times 9.8\times 0.6}=3.4m/s

According to law of conservation of momentum  

m_1u_1+m_2u_1=-m_1v_1+m_2v_2

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0.075\times 5.6+0=-0.075\times 3.4+0.4v_2

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b.Initial energy=\frac{1}{2}m_1v^2_x+m_1gh_1=\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 1.6=1.326 J

Final energy=\frac{1}{2}m_1v^2_x+m_1gh_2+\frac{1}{2}m_2v^2_2

Final energy=\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 0.6+\frac{1}{2}(0.4)(1.69)^2=1.162 J

Energy lost due to compact=Initial energy-final energy=1.326-1.162=0.164 J

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