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3 years ago

If you needed to find the force needed to pull a small car up a ramp it would be best to use -

Physics

2 answers:

krok68 [10]3 years ago

5 0

the answer would be a.a spring scale

Len [333]3 years ago

3 0

You can use a spring scale, however, if you have all the information needed for the formula, it is best to use it as it offers a more precise answer.

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Standing at a crosswalk, you hear a frequency of 550 Hz from the siren of an approaching ambulance. After the ambulance passes,

FromTheMoon [43]

There are six steps to this process , I uploaded step one and as you can see you can get all six on Quizlet:). Good luck

6 0

3 years ago

A box has the dimensions of 50 cm × 30 cm × 15 cm, weighs 150 N, and is to be

nadezda [96]

The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

<h3>What is pressure?</h3>

The physical force used to apply pressure to an object is defined as such. Per square inch of an object, a force is applied perpendicularly to its surface. For pressure, the fundamental formula is F/A. (Force per unit area). The Pascal is the unit of pressure (Pa).

The four different types of pressure are absolute, atmospheric, differential, and gauge pressure. Have you ever noticed that when you use a straw to drink something, the air actually gets suked out? In reality, you're applying "Pressure" as you drink the beverage.

A box has the dimensions of 50 cm × 30 cm × 15 cm

Let each face be A, B and C

The weight of the box = 150 N

Formula for pressure is

P = F/A

To find out which face of the box can withstand a pressure of 0.25 N/cm

we need find the area of each face and find its pleasure

Face A = 50 cm × 30 cm

Area A = l × b

= 50 × 30

= 1500 cm²

Pressure A = 150/1500

= 0.1 N/cm³

0.25 > 0.1

The surface can definitively withstand the pressure of Face A

Face B = 30 cm × 15 cm

Area A = l × b

= 30 × 15

= 450 cm²

Pressure A = 150/450

= 0.3 N/cm³

0.25 < 0.3

The surface could not withstand the pressure of Face B

Face C = 50 cm × 15 cm

Area A = l × b

= 50 × 15

= 750 cm²

Pressure A = 150/750

= 0.2 N/cm³

0.25 > 0.2

The surface can definitively withstand the pressure of Face C

Thus, The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

Learn more about Pressure

brainly.com/question/945436

#SPJ9

8 0

1 year ago

Helpp pleaseeeeee …..

Lilit [14]

Answer:

300 cos 30 = 40 a + 40 * .2 * 10

Total force = mass * acceleration + frictional force

260 = 40 a + 80

a = 180 / 40 = 4.5 m/s^2

Check:

15 a + 15 * 10 * .2 = T acceleration of 15 kg block (assuming a = 4.5)

T = 15 (4.5) + 30 = 97.5 force required to accelerate 15 kg block

260 - 97.5 = 162.5 net force on 25 kg block

162.5 = 4.5 (25) + 25 * 10 * .2

162.5 = 112.5 + 50 = 162.5

4.5 m/s^2 checks out as correct

8 0

2 years ago

One differnce between magnetic poles and elcyrical charges is that

Sphinxa [80]

Answer:

In the electric field, the like charges repel each other, and the unlike charges attract each other, whereas in a magnetic field the like poles repel each other and the unlike poles attract each other.

Explanation:

8 0

3 years ago

An airplane maintains a speed of 585 km/h relative to the air it is flying through as it makes a trip to a city 815 km away to t

navik [9.2K]

Answer:

a) t = 1.47 h b) t = 1.32 h

Explanation:

a) In this problem the plane and the wind are in the same North-South direction, whereby the vector sum is reduced to the scalar sum (ordinary). Let's calculate the total speed

v = $v_{f}$ f - $v_{w}$

v = 585 -32.1

v = 552.9 km / h

We use the speed ratio in uniform motion

v = x / t

t = x / v

t = 815 /552.9

t = 1.47 h

b) We repeat the calculation, but this time the wind is going in the direction of the plane

v= $v_{f}$ f - $v_{w}$

v 585 + 32.1

v = 617.1 km / h

t = 815 /617.1

t = 1.32 h

4 0

3 years ago