Hello there,
Your correct answer would be 8.<span> There are </span>8 valence electrons<span> available for the Lewis structure for NH</span>3<span>.
Hope this helps
~Hottwizzlers</span>
Answer:
The answer to your question is: letter A.
Explanation:
A Covalent bond polar is between 2 non metals where one atom is bigger than the other one so the distribution of charges creates this polarity.
A. One atom attracts shared electrons more strongly than the other atom This is the correct definition of bond polar, one element is bigger and stronger than the other element.
B. One atom has transferred its electrons completely to another atom This definition is incorrect, it is the definition of ionic bonding.
C. A sea of electrons has been created between the elements This definition is incorrect for the polar bond, it describes a metallic bonding.
D. Two atoms are sharing electrons with equal attraction This definition is incorrect for a polar bond, but is the correct definition for nonpolar bonding.
Answer: 11.5 grams
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution
where,
Morality = 0.612 M
n= moles of solute
= volume of solution in ml = 100 ml
Now put all the given values in the formula of molarity, we get

Therefore, the mass of copper (II)nitrate required is 11.5 grams
Answer:
D
Explanation:
Oxygen is the 8th element in the periodic table. This means that oxygen has 8 protons and 8 electrons. In order to get the number of neutrons you take the atomic weight in this case 15.9999~16 and you subtract it by the number of protons (16-8).
Answer:
the electric field at Z = 12 cm is E = 9.68 × 10³ N/C = 9.68 kN/C
Explanation:
Given: radius of disk, R = 2.0 cm = 2 × 10⁻² cm, surface charge density,σ = 6.3 μC/m² = 6.3 × 10⁻⁶ C/m², distance on central axis, z = 12 cm = 12 × 10⁻² cm.
The electric field, E at a point on the central axis of a charged disk is given by E = σ/ε₀(
)
Substituting the values into the equation, it becomes
E = σ/ε₀(
) = 6.3 × 10⁻⁶/8.854 × 10⁻¹²(
) = 7.12 × 10⁵(
) = 7.12 × 10⁵(1 - 0.9864) = 7.12 × 10⁵ × 0.0136 = 0.0968 × 10⁵ = 9.68 × 10³ N/C = 9.68 kN/C
Therefore, the electric field at Z = 12 cm is E = 9.68 × 10³ N/C = 9.68 kN/C