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STALIN [3.7K]
3 years ago
14

5. If a spring with a 40 N/m spring constant is used to push a 10 kg ball to a speed of 2 m/s,

Physics
1 answer:
kolbaska11 [484]3 years ago
3 0

By compressing the spring a distance <em>x</em> (in m), you are storing 1/2 <em>k</em> <em>x</em> ² (in J) of potential energy, which is converted completely into kinetic energy 1/2 <em>m v</em> ², where

• <em>k</em> = 40 N/m = spring constant

• <em>m</em> = 10 kg = mass of the ball

• <em>v</em> = 2 m/s = ball's speed (at the moment the spring returns to its equilibrium point)

So we have

1/2 <em>k</em> <em>x</em> ² = 1/2 <em>m</em> <em>v</em> ²

<em>x</em> = √(<em>m</em>/<em>k</em> <em>v</em> ²) = √((10 kg) / (40 N/m) (2 m/s)²) = 1 m

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The time taken by the pulse to travel from one support to the other is 0.208 s.

<h3>Given:</h3>

The mass of the cord is m = 0.65 kg.

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The time taken by the pulse to travel from one support to the other is given as,

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Learn more about tension here:

brainly.com/question/24994188

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