This problem has three questions I believe:
>
How hard does the floor push on the crate?
<span>We have to find the net
vertical (normal) Fn force which results from Fp and Fg.
We know that the normal component of Fg is just Fg, which is equal to as 1110N.
From the geometry, the normal component of Fp can be calculated:
Fpn = Fp * cos(θp)
= 1016.31 N * cos(53)
= 611.63 N
The total normal force Fn then is:
Fn = Fg + Fpn
= 1110 + 611.63
=
1721.63 N</span>
> Find the friction
force on the crate
<span>We
have to look for the net horizontal force Fh which results from Fp and Fg.
Since Fg is a normal force entirely, so we can say that the
horizontal component is zero:
Fh = Fph + Fgh
= (Fp * sin(θp)) + 0
= 1016.31 N * sin(53)
=
811.66 N</span>
> What is the minimum
coefficient of static friction needed to prevent the crate from slipping on the
floor?
We just need to compute the
ratio Fh to Fn to get the minimum μs.
μs = Fh / Fn
= 811.66 N / 1721.63 N
<span>=
0.47</span>
The car A and car B are travelling at different speeds. The car that has a greater acceleration is car B.
<h3>What is acceleration?</h3>
Acceleration is defined as the rate change of velocity with time.
acceleration a = (Δv) / (Δt)
Car A is traveling with a constant velocity of 18 [m/s]. The initial and final velocity is same. So, the acceleration is given by
a = (18 -18)/ t
a = 0 m/s²
Car B speeds up from 0 [m/s] to 10 [m/s] in 4 seconds. The acceleration is
a = (10 -0)/ 4
a = 2.5 m/s²
Thus, the car B has greater acceleration.
Learn more about acceleration.
brainly.com/question/12550364
#SPJ1
Answer:
sp3d
Explanation:
=1
sp=2
sp^2=3
sp^3=4
sp^3d=5
As we add, we can make one more bond...since this says MORE than four bond, the answer must be sp^3d.
Explanation:
Potential energy is the energy obtained by an object due to the position of an object. Whereas kinetic energy is the energy obtained by an object due to its motion.
For example, an ball is placed over a building of height h. Then steps followed to covert its potential energy into kinetic energy are as follows.
Step 1: When ball is at placed over a building of height h, then it has only potential energy and no kinetic energy.
Step 2: A man pushes the ball and it moves in the downward direction.
Step 3: When ball starts to move or fall it gains kinetic energy, that is potential energy now becomes equal to 0.
Similarly, on reaching the ground and after bouncing a few times when it stop moving then kinetic energy converts into potential energy.
Answer:
a) 
b) No, the ray will not penetrate into the water since 73.7° is greater than the critical angle.
Explanation:
Given that:
refractive index of oil, 
angle of incidence, 
refractive index of water, 
(a)
Snell's law states that when a ray of light travels from a denser medium to a rarer medium its speed increases and it bends away from the normal. Likewise, when a ray of light travels from a rarer medium to a denser medium its speed slows down and it bends towards the normal.
Mathematically:
................................(1)
where the subscripts 1 & 2 denote for the incident ray and the refracted ray respectively.
Critical angle is that angle of incident of a ray of light through the optically denser medium on the two medium interface after which the refracted ray makes an angle of 90 degrees to the normal in the rarer medium.
- This is in accordance with the Snell's law that as we keep on increasing the the angle of incident on the optically denser side the angle of refraction keeps on increasing on the rarer side.
Now, using Snell's law eq. (1):
is the critical angle.
(b)
Since we have critical angle 65.92 degrees, so any value of the angle of incidence greater than that will lead to the reflection of the light from the interface of the two mediums, this phenomenon is called the total internal reflection.
