3 years ago

The density of gold is 19.3 g/cm3. what volume would 131.2 g of gold have?

Chemistry

1 answer:

Luda [366]3 years ago

5 0

Volume would be 6.79792764 cm³. Just divide 131.2 by 19.3

ρ=Mass/Volume
Volume= mass/density

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The percent composition of carbon in C6H12O6 is:

nata0808 [166]

To calculate percent composition, you first need to find the molar mass of C (carbon), H (hydrogen) and O (oxygen).
C is 12.01
H is 1.00
O is 16

Then multiply each by the number of atoms of each element in the formula (the number that comes after each element in the equation for example C6 means 6 carbon atoms.

C: 12.01 x 6= 72.06
H: 1x12= 12
O: 16x6= 96

Then add them up.
72.06+ 12+ 96= 180.06

Now find the percent composition of carbon.

72.06/ 180.06 x 100= 40.01%

So the answer is C 40%.

8 0

3 years ago

The labeled images each represent the wave patterns found in the electromagnetic wave spectrum. Which image is correctly labeled

Nataly_w [17]

Https://us-static.z-dn.net/files/d15/c111c5e1b23135c61adec7b554629964.jpg

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