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2 years ago

6

Differentiate between acids and bases on the basis of their pH values Give an example of each type. Please help worth 100 points

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1 answer:

gtnhenbr [62]2 years ago

3 0

Answer: Well 0-7 is acid, and 0-3 is a strong acid. 4-7 is a weak acid. 8-11 is strong base. 12-14 is weak base!

Explanation:

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Write the general electron configuration of a transition element(b) in Period 6.

aksik [14]

The general electronic configuration of transition element is (n−1)d1−10ns1−2.

<h3>What are the transition element in period 6?</h3>

The period 6 transition metals are;

Lanthanum (La), Hafnium (Hf), Tantalum (Ta), Tungsten (W),

Rhenium (Re), Osmium (Os), Iridium (Ir), pPatinum (Pt),

Gold (Au), and Mercury (Hg).

As a rule, period 6 elements fill their 6s shells first, then their 4f, 5d, and 6p shells, in that order.

However, there are exceptions, such as gold.

To learn more about transition element, refer

https://brainly.in/question/27629573

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6 0

2 years ago

A cube has sides that are 0.03 m . What is the volume of the cube in liters?

Marizza181 [45]

Answer:

0.027 litres

Explanation:

volume of cube = length × base area

volume of cube = 0.03m ×( 0.03m × 0.03m )

volume of cube = 0.03m × ( 0.0009m^2 )

volume of cube = 0.000027m^3

1 cubic metre = 1000 litres

0.000027m^3 = 0.027 litres

8 0

3 years ago

Look at the periodic table.

zhuklara [117]

Answer:

$Mg^{+2}$

Explanation:

The oxidation state of S is (-2) and that of Mg is (+2) since Mg loses two electrons to S

5 0

3 years ago

1,4-Pentadiene has a AHhydro = -254 kJ/mol while trans-1,3-pentadiene has a AHhydra = -226 kJ/mol. Explain this difference in he

julsineya [31]

Answer:

trans-1,3-pentadiene is more stable than 1,4-pentadiene due to presence of a conjugated double bond.

Explanation:

Here, $\Delta H_{hydro}=H(hydrogenated pdt.)-H(diene)$

H(hydrogenated pdt.) is same for both 1,4-pentadiene and 1,3-pentadiene as they both produce pentane after hydrogenation

H(diene) depends on stability of diene.

More stable a diene, lesser will be it's H(diene) value (more neagtive).

trans-1,3-pentadiene is more stable than 1,4-pentadiene due to presence of a conjugated double bond.

Hence, $\Delta H_{hydro}$ is higher (less negative) for trans-1,3-pentadiene

5 0

3 years ago

Consider the following unbalanced chemical equation. C5H12(l) + O2(g) → CO2(g) + H2O(l) If 21.9 grams of pentane (C5H12) are bur

Marina CMI [18]

Answer : The mass of water produced will be 32.78 grams.

Explanation : Given,

Mass of $C_5H_{12}$ = 21.9 g

Molar mass of $C_5H_{12}$ = 72.15 g/mole

Molar mass of $H_2O$ = 18 g/mole

First we have to calculate the moles of $C_5H_{12}$ .

$\text{Moles of }C_5H_{12}=\frac{\text{Mass of }C_5H_{12}}{\text{Molar mass of }C_5H_{12}}=\frac{21.9g}{72.15g/mole}=0.3035moles$

Now we have to calculate the moles of $H_2O$ .

The balanced chemical reaction will be,

$C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)$

From the balanced reaction we conclude that

As, 1 mole of $C_5H_{12}$ react to give 6 moles of $H_2O$

So, 0.3035 moles of $C_5H_{12}$ react to give $0.3035\times 6=1.821$ moles of $H_2O$

Now we have to calculate the mass of $H_2O$ .

$\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O$

$\text{Mass of }H_2O=(1.821mole)\times (18g/mole)=32.78g$

Therefore, the mass of water produced will be 32.78 grams.

3 0

3 years ago