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julsineya [31]
3 years ago
15

Select the best answer.

Chemistry
1 answer:
madreJ [45]3 years ago
8 0
Answer: All of these I’m pretty sure

Explanation: It just makes sense
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Consider the formula al2(so4)3. how many atoms of aluminum are present?
Shkiper50 [21]
2 atoms of aluminium
3 0
3 years ago
If your really kind please help I just want help
Eva8 [605]
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4 0
4 years ago
Al agregar 150g de una sustancia X en un recipiente que sostiene que contiene agua hasta 50, el nivel del agua aumenta hasta 120
vovangra [49]

Answer:

2,14 g / ml

Explanation:

Sabemos que el volumen de una sustancia es igual al cambio de volumen del agua cuando el objeto en cuestión se sumerge en el agua.

Dado que el volumen original del agua = 50 ml

Volumen de agua después de sumergir el objeto = 120 ml

Masa del objeto = 150 g

Ahora,

Densidad = masa / volumen

Densidad = 150g / 120-50 ml

Densidad = 150/70 ml

Densidad = 2,14 g / ml

4 0
3 years ago
A cube of an unknown metal is 1.25 inches on each side and has a mass of 128.3741 g. What is its' density?
Mademuasel [1]
Hey there!

To find the density of an object, you must use this formula:
Density=Mass/Volume

Knowing that your mass is 128.3741, the only information you need left would be to find the volume of the cube.

Because the side length of the cube is given, you can multiply the length three times in order to find its volume:
1.25*1.25*1.25
=1.953125

Now that you have your volume and mass, divide the mass by the volume to find the density:
128.3741/1.953125
=65.7275392

Therefore, your density would be 65.7275392 grams per inches cubed.
6 0
3 years ago
A certain amount of hydrogen peroxide was dissolved in 100. mL of water and then titrated with 1.68 M KMnO4. What mass of H2O2 w
Stels [109]

Answer:

see explanation below

Explanation:

First to all, this is a redox reaction, and the reaction taking place is the following:

2KMnO4 + 3H2SO4 + 5H2O2 -----> 2MnSO4 + K2SO4 + 8H2O + 5O2

According to this reaction, we can see that the mole ratio between the peroxide and the permangante is 5:2. Therefore, if the titration required 21.3 mL to reach the equivalence point, then, the moles would be:

MhVh = MpVp

h would be the hydrogen peroxide, and p the permanganate.

But like it was stated before, the mole ratio is 5:2 so:

5MhVh = 2MpVp

Replacing moles:

5nh = 2MpVp

Now, we just have to replace the given data:

nh = 2MpVp/5

nh = 2 * 1.68 * 0.0213 / 5

nh = 0.0143 moles

Now to get the mass, we just need the molecular mass of the peroxide:

MM = 2*1 + 2*16 = 34 g/mol

Finally the mass:

m = 0.0143 * 34

m = 0.4862 g

8 0
3 years ago
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