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marin [14]
3 years ago
12

The mass ratio of H to O in water (H2O) is 1:8. What is the mass

Chemistry
1 answer:
svp [43]3 years ago
4 0

Answer: 1:16

Explanation:

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An unknown solution has a pH of 7.2. Which of these chemicals is likely to cause the greatest decrease in the pH of the solution
prohojiy [21]

Answer:

HNO₃.

Explanation:

  • It is known that acids decrease the pH of the solution, while bases increase  the pH of the solution.

So, HF and HNO₃ decrease the pH of the solution as they produce H⁺ in the solution.

While, KOH and NH₃ increase the pH of the solution as they produce OH⁻ in the solution.

HNO₃ will decrease the pH of the solution greater than HF.

  • Because HNO₃ is strong acid that decomposes completely to produce H⁺ more than the same concentration of HF that is a weak acid which does not decomposed completely to produce H⁺.
7 0
3 years ago
imagine that you go into the lab and perform a titration. you measure 40 ml of your analyte and add it to an erlenmeyer flask. t
mote1985 [20]

The Molar concentration of your analyte solution is 1.17 m

<h3>What is titration reaction?</h3>
  • Titration is a chemical analysis procedure that determines the amount of a sample's ingredient by adding a precisely known amount of another substance to the measured sample, with which the desired constituent reacts in a specific, known proportion.

Make use of the titration formula.

The formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base.

if the titrant and analyte have a 1:1 mole ratio. (Molarity is a measure of a solution's concentration represented as the number of moles of solute per litre of solution.)

26 x 1.8 = 40 x M

M = 26 x1.8 /40

M = 1.17

The Molar concentration of your analyte solution is 1.17 m

To learn more about Titration  refer,

brainly.com/question/186765

#SPJ4

5 0
1 year ago
An orbital of an atom is defined as the most probable location of(1) an electron (2) a neutron (3) a positron (4) a proton
Montano1993 [528]

Answer: option (1) an electron.


Justification:


1) The plum pudding model of the atom conceived by the scientist J.J. Thompson, described the atom as a solid sphere positively charged with the electrons (particles negatively charged) embedded.


2) The next model of the atom, developed by the scientist Ernest Rutherford, depicted the atom a mostly empty space with a small dense positively charged nucleous and the electrons surrounding it.


3) Then, Niels Bhor came out with the model of electrons in fixed orbits around the nucleous, just like the planets orbit the Sun. So, the path followed by the electrons were orbits.


4) The quantum model of the atom did not place the electrons in fixed orbits around the nucleous but in regions around the nucleous. Those regions were named orbitals. And they are regions were it is most probable to find the electron, since it is not possible to tell the exact position of an electron.


As per this model, the electron has a wave function associated. The scientist Schrodinger developed the wave equation which predicts the location of the electron as a probability.


The orbitals are those regions were it is most likely to find the electron. Those regions are thought as clouds of electrons.

5 0
3 years ago
Read 2 more answers
Assume that silver and gold form ideal, random mixtures. Calculate the mass of pure Ag needed to cause an entropy increase of 20
KengaRu [80]

Answer:

m_{Ag}=2,265.9g

Explanation:

Hello!

In this case, since the definition of entropy in a random mixture is:

\Delta S=-n_TR\Sigma[x_i*ln(x_i)]

For this silver-gold mixture we write:

\Delta S=-(n_{Au}+n_{Ag})R\Sigma[\frac{n_{Au}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Au}}{n_{Au}+n_{Ag}} )+\frac{n_{Ag}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Ag}}{n_{Au}+n_{Ag}} )]

By knowing the moles of gold:

n_{Au}=100g*\frac{1mol}{197g} =0.508mol

It is possible to write the aforementioned formula in terms of the variable x representing the moles of silver:

20\frac{J}{mol}=-(0.508+x)8.314\frac{J}{mol*K} \Sigma[\frac{0.508}{0.508+x} *ln(\frac{0.508}{0.508+x} )+\frac{x}{0.508+x} *ln(\frac{x}{0.508+x} )]

Which can be solved via Newton-Raphson or a solver software, in this case, I will provide you the answer:

x=n_{Ag}=21.0molAg

So the mass is:

m_{Ag}=21.0mol*\frac{107.9g}{1mol}\\ \\m_{Ag}=2,265.9g

Best regards!

3 0
3 years ago
What observations can you make about this group of people?
DedPeter [7]

Answer:The people are part of a softball team. They appear happy, they are showing number one with their fingers, and they are holding a trophy. They probably won the softball league championship

Explanation:

7 0
3 years ago
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