Answer:
The latent heat of fusion of water is 334.88 Joules per gram of water.
Explanation:
Let the latent heat of ice be 'x' J/g
1) Thus heat absorbed by 100 gram of ice to get converted into water equals
2) heat energy required to raise the temperature of water from 0 to 25 degree Celsius equals
Thus total energy needed equals 
3) Heat energy released by the decrease in the temperature of water from 25 to 11 degree Celsius is
Now by conservation of energy we have
The work done by tension force of 14N applied on the laptop by a rope as it moves 2.0 mm up the slope is 0.028 J
W = F d cos θ
W = Work done
F = Force
d = Displacement
θ = Angle between force and displacement vector
F = 14 N
d = 2 mm = 0.002 m
θ = 0
W = 14 * 0.002 * 1
W = 0.028 J
Work done is the change in energy of an object. So if an object moves a certain distance, work is done on the object. If the force and displacement are perpendicular to each other there is no work done on the object.
Therefore, the work done by tension on the laptop is 0.028 J
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Answer:
Explanation:
When we are driving we need a lot of attention and concentration. Also one involved in driving should be consious and courteous
Thus, whenever a person is drives, and when he is disactracted by Mobile phones it will destroy his presence of mind.
It will good if use mobile after stopping the vehicle
Thanks
Explanation:
The time taken by a wave crest to travel a distance equal to the length of wave is known as wave period.
The relation between wave period and frequency is as follows.
T = \frac{1}{f}T=
f
1
where, T = time period
f = frequency
It is given that wave period is 18 seconds. Therefore, calculate the wave period as follows.
T = \frac{1}{f}T=
f
1
or, f = \frac{1}{T}f=
T
1
= \frac{1}{18 sec}
18sec
1
= 0.055 per second (1cycle per second = 1 Hertz)
or, f = 5.5 \times 10^{-2} hertz5.5×10 −2 hertz
<h3>Thus, we can conclude that the frequency of the wave is 5.5 \times 10^{-2} hertz5.5×10 −2 hertz .</h3>
Answer:
The acceleration of the proton is 2.823 x 10¹⁷ m/s²
The acceleration of the electron is 5.175 x 10²⁰ m/s²
Explanation:
Given;
distance between the electron and proton, r = 7 x 10⁻¹⁰ m
mass of proton, 
= 1.67 x 10⁻²⁷ kg
mass of electron, 
= 9.11 x 10⁻³¹ kg
The attractive force between the two charges is given by Coulomb's law;
where;
k is Coulomb's constant = 9 x 10⁹ Nm²/c²
Acceleration of proton is given by;
F = ma
Acceleration of the electron is given by;
