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Lady_Fox [76]
3 years ago
14

Question 1 A car is moving with a positive acceleration. Which of the following accurately depicts the direction of its velocity

?
Physics
1 answer:
Mariulka [41]3 years ago
5 0
The velocity will be positive and linear.
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A plane is landing at an airport. The plane has a massive amount of kinetic energy due to it's motion. When the plane lands, it
marshall27 [118]

Answer:

A. The brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes

Explanation:

Based on the law of conservation of energy, the brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes.

The law of conservation of energy states that energy is neither created nor destroyed in a system but it is transformed from one form to another.

As the airplane slows down, the kinetic energy which is presented in the motion of the plane is gradually converted to potential energy.

The potential energy is the energy due to the position of a body.

8 0
2 years ago
When does an object falling vertically through the air reach terminal velocity?
zlopas [31]

Answer:

a. when the acceleration of the objects become negative

7 0
3 years ago
If the mass of the cart was increased but the hanging mass remained the same, how would the acceleration be affected? Explain ho
Margaret [11]

Answer:

It is always said that mass is same everywhere.

6 0
2 years ago
What three variable factors determine the force of gravity between any two objects?
brilliants [131]
The force of gravity between two objects is:
F = G*m1*m2/r^2

So, it is dependent of the two masses and the distance between their centers of mass.  
5 0
3 years ago
Problem 5 You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this gam
Dvinal [7]

Answer:

Option D: 1.5in in front of the target

Explanation:

The object distance is y= 6in.

Because the surface is flat, the radius of curvature is infinity .

The incident index is n_i=\frac{4}{3} and the transmitted index is n_t= 1.

The single interface equation is \frac{n_i}{y}+\frac{n_t}{y^i}=\frac{n_t-n_i}{r}

Substituting the quantities given in the problem,

\frac{\frac{4}{3}}{6in}+\frac{1}{y^i}= 0

The image distance is then y^i=-\frac{18}{4}in =-4.5in

Therefore, the coin falls 1.5in in front of the target

6 0
2 years ago
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