Answer:
The box will be moving at 0.45m/s. The solution to this problem requires the knowledge and application of newtons second law of motion and the knowledge of linear motion. The vertical component of the force Fp acts vertically upwards against the directio of motion. This causes a constant upward force of 23sin45° to act on the box. Fhe frictional force of 13N also acts vertically upwards and so two forces act upwards against rhe force of gravity resulting un a net force of 0.7N acting kn the box. This corresponds to an acceleration of 0.225m/s². So in w.0s after i start to push v = 0.45m/s.
Explanation:
Answer:
Magnitude of the horizontal force applied = 120N
Explanation:
The explanation and the FBD - free body diagram is shown in the attachment
From F = Miu(R)
Answer:
Answer:
a 100W light bulb costs one tenth of a kilowatt when used for one hour
so 6 hours = 6/10 of a kilowatt
= 6/10 of 6 = 3.6 Dinars
Answer:
b. varies inversely with the square of the distance from the center of Earth.
Explanation:
Comparing the Newton's law of universal gravitation and second law of motion;
from Newton's second law of motion,
F = ma ............. 1
from New ton's law of universal gravitation,
F = ........... 2
Equating 1 and 2, we have;
mg =
g =
Therefore, the acceleration due to gravity near Earth, g, is inversely proportional to the square of the distance from the center of Earth.