3 years ago

As I increase the frequency of a wave, what happens to the number of harmonics?

1 answer:

Serhud [2]3 years ago

5 0

I would say the number of harmonics decrease, because you're adding to the frequency of a wave.

I hope this helps :)

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elena-s [515]

First of all, we need to convert the angular speed from rev/min into rev/s:

$\omega_f=300 rev/min=5 rev/s$

The angular acceleration is the variation of angular speed divided by the time:

$\alpha=\frac{\omega_f-\omega_i}{t}=\frac{5 rev/s-0}{2 s}=2.5 rev/s^2$

And this is constant, so we can use the following equation to calculate the angle through which the engine has rotated:

$\theta(t)=\frac{1}{2}\alpha t^2 =\frac{1}{2}(2.5 rev/s^2)(2 s)^2=5 rev$

so, 5 revolutions.

3 0

2 years ago

Alika [10]

Answer:0.00285714285 seconds

Explanation:

period=1 ➗ frequency

Period=1 ➗ 350

Period=0.00285714285 seconds

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3 years ago

Margarita [4]

the answer is A or B

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3 years ago

sattari [20]

Density = Mass/Volume
So, given mass = 20 g and volume = 40 cm^3
By substituting in above equation, Density = 20/40 = 0.5 g/cm^3
Hope it helps.

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3 years ago

RSB [31]

Answer:

we use the formula,

$v {}^{2} = u {}^{2} + 2gh$

$89 {}^{2} = 76 {}^{2} + 2(10)h$

$h = (89 {}^{2} - 76 {}^{2} ) \div 20$

h= 107 m

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3 years ago