Answer:
A = 11 i believe
Step-by-step explanation:
You just do 50 - 43.89
It’s not that hard
Get a brain g
From the above definition, we can say that the cross-section, as a result of the plane intersecting the sphere through its centre, will be a circle with the radius "r" same as that of the given sphere. Thus, the area of the cross section is 15.2 m²
I’m pretty sure the answer is 60!!!!
Answer:
Hi there!
Your answer is:
n= 2/h - q^3
q= ![\sqrt[3]{\frac{2}{h}-n }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B2%7D%7Bh%7D-n%20%7D)
h= 2 / (n+q^3)
Step-by-step explanation:
2=(n+q^3)h
/h
2/h = (n+ q^3)
-q^3
2/h-q^3 = n
2=(n+q^3)h
/h
2/h = n+q^3
-n
2/h - n= q^3
= q
2= (n+q^3)h
/n+q^3
2 / (n+q^3) = h
Hope this helps and that edge is going well :D
Signed,
A fellow Edge Student ;)