Answer:
Explanation:
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In this case, since the buffer is not given, we assume it is based off ammonia, it means the ammonia-ammonium buffer, whereas the ammonia is the weak base and the ammonium ion stands for the conjugate acid. In such a way, when adding HI to the solution, the base of the buffer, NH3, reacts with the former to promote the following chemical reaction:
Because the HI is totally ionized in solution so the iodide ion becomes an spectator one.
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The resistance of the heating element is 21.61 Ω
Given
The power dissipated = 1500 W
Voltage = 180 V
We know that
Power = Voltage * Current
⇒ Power / Voltage = Current
⇒ 1500 W/180 V = Current
⇒ 8.33 A = Current
In order to calculate the resistance of the heating element. We Have to apply the formula
Power = (Current)^2 * Resistance
⇒ Resistance = Power / (Current)^2
⇒ Resistance = 1500 W/ (8.33) ^2
⇒ Resistance = 21.61 Ω
Hence the resistance of the heating element is 21.61 Ω
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I think it’s B. At least that’s what makes sense to me
Answer:
The pH of the solution is 4.282
Explanation:
First we need to write the dissociation reaction
⇄
Also, we need to prepare I C E table
⇄
I 0.078 0 0
C - x +x +x
E 0.078 - x x x
Thus, pH= - Log[H₃O⁺]
The equilibrium concentration of H₃O⁺ = x
So, we solve for x
Solving this quadratic equation; x = 5.2232 x 10⁻⁵ M
pH = - Log[H₃O⁺]
pH = - Log[5.2232 x 10⁻⁵]
pH = 4.282 (in 3 decimal places)
Therefore, the pH of the solution is 4.282