1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natalka [10]
3 years ago
12

Are fruits and juices acid are base or acids or both​

Chemistry
2 answers:
Jlenok [28]3 years ago
7 0

Answer: Acidic liquids have low pH levels. Many fruit juices qualify as acidic liquids. Some of the more acidic fruit juices are orange juice, lemon juice, grapefruit juice, tomato juice and red currant juice.

Explanation:

stiks02 [169]3 years ago
7 0

Answer:Acids and bases are common substances found in many every day items, from fruit juices and soft drinks to soap. In this chapter, we will examine the properties of acids and bases, and learn about the chemical nature of these important compounds.While a few fruit juices are more acidic than others, many fruit juices share the same level of acidity, and vegetable juices have the lowest amount of acid. Fruit juice is more acidic than vegetable juice.

Explanation: so its both

You might be interested in
What happens when an electron moves from a higher energy level to a lower one
hjlf
When an electron moves from a higher to a lower energy level, energy is released (often as light).
4 0
4 years ago
Is NaF an acid, base or salt?
Ymorist [56]

Answer:

NaF is a salt

4 0
3 years ago
Read 2 more answers
The students who conducted the shadow length experiment concluded that their results concluded that their results supported thei
scZoUnD [109]
Confirmation bias<span>, also called </span>confirmatory bias<span> or </span>myside bias, is the tendency to search for, interpret, favor, and recall information in a way that confirms one's preexisting beliefs or hypotheses, while giving disproportionately less consideration to alternative possibilities.[Note 1][1]<span> It is a type of </span>cognitive bias<span> and a systematic error of </span>inductive reasoning<span>. People display this bias when they gather or remember information selectively, or when they interpret it in a </span>biased way<span>. The effect is stronger for </span>emotionally<span> charged issues and for deeply entrenched beliefs. People also tend to interpret ambiguous </span>evidence<span> as supporting their existing position. Biased search, interpretation and memory have been invoked to explain </span>attitude polarization<span> (when a disagreement becomes more extreme even though the different parties are exposed to the same evidence), </span>belief perseverance<span> (when beliefs persist after the evidence for them is shown to be false), the irrational primacy effect (a greater reliance on information encountered early in a series) and </span>illusory correlation<span> (when people falsely perceive an association between two events or situations).</span>
6 0
3 years ago
A 2.300×10−2 m solution of nacl in water is at 20.0∘c. the sample was created by dissolving a sample of nacl in water and then b
lilavasa [31]

The given question is incomplete. The complete question is as follows.

A 2.300×10−2 m solution of nacl in water is at 20.0∘c. the sample was created by dissolving a sample of nacl in water and then bringing the volume up to 1.000 l. it was determined that the volume of water needed to do this was 999.4 ml . the density of water at 20.0∘c is 0.9982 g/ml.

Calculate the molality of the salt solution.

Express your answer to four significant figures and include the appropriate units.

Explanation:

Molality is defined as the number of moles present in kg of a solvent.

Mathematically,     Molality = \frac{\text{moles of solute}}{\text{mass of solvent}}

Also,

      Mole of solute = Molarity of solute x Volume of solution

                               = (0.0230 M) x (1.000 L) = 0.0230 mol of solute

Therefore, mass of solvent will be as follows.

     999.4 mL \times (\frac{0.9983 g}{1 mL})

                  = 997.7 g

                  = 0.9977 kg        (as 1 kg = 1000 g)

Therefore, we will calculate the molality as follows.

          Molality = \frac{0.0230 mol}{0.9977 kg}

                   = 0.02306 mol/kg

thus, we can conclude that molality of the given solution is 0.02306 mol/kg.

8 0
3 years ago
a 15.0 L tank of gas is contained at a high pressure of 8.20*10^4. The tank is opened and the gas expands into an empty chamber
Nostrana [21]

Answer:

P_2=20.5

Explanation:

Assuming that temperature is constant

According to Boyle's Law, at constant temperature pressure is inversly proportional to the volume  and mathematically it can be expressed as:

P_1V_1 = P_2V_2..........1

P_1=8.2 \times 10^4

P_2=?

V_1=15L

V_2=6.00 \times 10^4L

from the first equation after putting all the value

we get,

P_2=20.5

8 0
3 years ago
Other questions:
  • Do you believe that in 2020 every single American, regardless of race, sex, or income level, has an equal opportunity to achieve
    14·2 answers
  • What elements react the most? Like have the most reactivity.
    12·1 answer
  • In a closed container with a fixed volume, when the temperature of a gas doubles, the pressure of the gas is?
    10·1 answer
  • How many moles of O2 are contained in 32 grams of O2?
    14·1 answer
  • My Plate recommends that ______ of your nutritional intake comes from fruits and vegetables.
    15·2 answers
  • 6.201cm+7.4cm+0.68 cm+12.0cm
    11·1 answer
  • In the background information, it was stated that CaF2 has solubility, at room temperature, of 0.00160 g per 100 g of water. How
    14·1 answer
  • the volume of a substance must be measured several time during an experiment. which units should be used to measure the volume o
    10·1 answer
  • Explain how atoms organize to create larger structures?
    14·1 answer
  • plantea una posible solucion a la siguiente situacion, empleando una de las tecnicas de la biotecnologia. en una ciudad se ha co
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!