D is the answer I believe.
The volume occupied by 0.102 mole of the helium gas is 2.69 L
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Number of mole (n) = 0.102 moles
- Pressure (P) = 0.95 atm
- Temperature (T) = 305 K
- Gas constant (R) = 0.0821 atm.L/Kmol
- Volume (V) =?
<h3>How to determine the volume </h3>
The volume of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both sides by P
V = nRT / P
V = (0.102 × 0.0821 × 305) / 0.95
V = 2.69 L
Thus, the volume of the gas is 2.69 L
Learn more about ideal gas equation:
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Answer:
5 m/s 2
Explanation:
if the car moved from 00 to 1-5 then to 2_10 you can know that it is going up in velocity but 5 a second so 5 m a second. hope this helps
Answer:
a) 30 moles
Explanation:
2C6H6 + 1502 -------> 12CO2 + 6H20
from reaction 2 mol 15 mol
given 4.0 mol x mol
x = 4.0*15/2 = 30. mol
Answer:
Chemical formula of Oxygen is O2.
We know ,
1 mole of a substance contains 6.022×10^23, Avogadro’s Constat.
Here, Molar mass of O = 16u
And molar mass of O2 = 32u
And 32g of O2 = 1 mole of O2
It means that,
32g of O2 = 6.022×10^23 molecules
