1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Wewaii [24]
2 years ago
13

How many molecules make up 32 g of Oz?

Chemistry
2 answers:
aivan3 [116]2 years ago
6 0

Answer:

The correct answer is given in the picture

<em><u>This</u></em><em><u> </u></em><em><u>ANSWER</u></em><em><u> </u></em><em><u>IS</u></em><em><u> </u></em><em><u>ONLY</u></em><em><u> </u></em><em><u>CORRECT</u></em><em><u> </u></em><em><u>WHEN</u></em><em><u> </u></em><em><u>Oz</u></em><em><u> </u></em><em><u>STAND</u></em><em><u> </u></em><em><u>FOR</u></em><em><u> </u></em><em><u>OZONE</u></em><em><u> </u></em>

Orlov [11]2 years ago
4 0

Answer:

Chemical formula of Oxygen is O2.

We know ,

1 mole of a substance contains 6.022×10^23, Avogadro’s Constat.

Here, Molar mass of O = 16u

And molar mass of O2 = 32u

And 32g of O2 = 1 mole of O2

It means that,

32g of O2 = 6.022×10^23 molecules

You might be interested in
Which statement best describes the relationship between observations and conclusions? A. Observations are based on Conclusions B
irga5000 [103]

Answer:

B. Conclusions are based on observations

Explanation:

7 0
3 years ago
Sodium metal reacts with chlorine gas to produce sodium chloride. What mass (grams) of sodium metal would be needed to fully rea
gulaghasi [49]

Answer:

105.8 g of Na would be required

Explanation:

Let's think the reaction:

2Na(s)  + Cl₂(g)  →  2NaCl (s)

1 mol of chlorine reacts with 2 moles of sodium

Then, 2.3 moles of Cl₂ would react with (2.3 .2) / 1 = 4.6 moles

Let's determine the mass of them.

4.6 mol . 23 g/mol = 105.8 g

3 0
3 years ago
What types of atoms release nuclear radiation
djyliett [7]
Isotopes of elements where the nucleas is unstable generally release nuclear radiation. So unstable atoms
4 0
3 years ago
What is the molar mass of citric acid (c6h8o7) and baking soda (nahco3)?
Rufina [12.5K]

The molar mass of citric acid (c6h8o7) is 192.124g/mol

The molar mass of baking soda (nahco3) is 84.007g/mol

The molar mass of a chemical compound is defined as the mass of a sample of that compound divided by the amount of substance in that sample and is measured in moles. Molar mass is a mass property, not a molecular property of a substance.

Molar mass is the mass of 1 mole of the sample. To find the molar mass, add up the atomic masses (atomic weights) of all the atoms in the molecule. Use the masses listed in the periodic table or atomic weight table to determine the atomic mass of each element.

Learn more about molar mass here:brainly.com/question/15476873

#SPJ1

6 0
2 years ago
Read 2 more answers
What Most Often Causes The Availability Of Water To Change?
Margaret [11]

Answer:the answer is C

Explanation:

8 0
3 years ago
Other questions:
  • Jose and Sarah are running in the cross country meet. Their skeletal and muscular systems work to move them through the course.
    7·1 answer
  • What is the chemical formula for acetone
    9·2 answers
  • Which statement best summarizer the importance of ernest rutherford's gold foil experiment
    11·2 answers
  • How will adding NaCl affect the freezing point of a solution?
    15·2 answers
  • Please help me out asap
    6·2 answers
  • Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing tin
    11·1 answer
  • The oxidation number of magnesium in magnesium chloride is _____.
    15·1 answer
  • This refers to the most powerful means of communicating confidence and conviction A.Posture B.eye contact C.body movement
    15·1 answer
  • Need help!!!!!!!!!!!!!
    10·1 answer
  • All participants in the Genius dog challenge are border collies which some experts think are the what breed of dog?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!